[英]Delete list element by index from another list value
我有一个算法生成的列表:
L1 = [1, 2]
我还有第二个清单:
L2 = [10, 20, 30, 40, 50]
如何通过L1
值中的索引删除L2
的元素?
这是我的代码不起作用:
L1 = [1, 2]
L2 = [10, 20, 30, 40, 50]
for i in L1:
for k,v in enumerate(L2):
if i == k:
L2.remove(v)
高效:
>>> for i in sorted(L1, reverse=True):
... L2.pop(i)
如果列表不是特别大,则可以使用列表理解来构建新列表:
>>> L1 = [1, 2]
>>> L2 = [10, 20, 30, 40, 50]
>>> S1 = set(L1)
>>> [el for i, el in enumerate(L2) if i not in S1]
[10, 40, 50]
建立新清单:
In[9]: L1 = [1,2]
L2 = [10,20,30,40,50]
In[10]: [x for i,x in enumerate(L2) if i not in L1]
Out[10]: [10, 40, 50]
您可以这样做:
L1 = [1,2]
L2 = [10,20,30,40,50]
L2 = [x for x in L2 if L2.index(x) not in L1]
输出:
[10, 40, 50]
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