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如何寻址浮点数以在C中向其写入4个单独的字节?

[英]How to address a float to write 4 individual bytes to it in C?

我有一个函数,期望32位浮点数,但是在某种模式下,它期望浮点数实际上只是打包在一起的4x UINT8s。

我编写的代码有效,但是我得到了编译器警告“非法指针”警告,并且我想知道最“正确”的方法是什么? 代码的可读性也非常重要,尽管可能有更少的代码编写方式,但我认为我写的内容很容易阅读。

UINT8 time[6];
FLOAT FSTtime = 0;    //32bit float
UINT8 * FSTtimePointer;

//Get the current time as 6 bytes {secs,mins,hours,day,month,year}
returnSize = appP->DB_get_param_value(12, 0, 8, &time);
if (returnSize < 6) return;

(UINT8*)FSTtimePointer = &FSTtime;   //Line 876

//Pack 4 bytes of time data into a "float"
FSTtimePointer [0] = time[3];  //Reverse month & day because americans are backwards
FSTtimePointer [1] = time[4];
FSTtimePointer [2] = time[2];
FSTtimePointer [3] = time[1];

appP->HIST_write_FST_log(SubMin_CFG.OFFSET, (UINT16)historyPointer, FSTtime);

HIST_write_FST_log的原型是

  void   (*HIST_write_FST_log) (UINT8 hist_pt_index, UINT16 log_index, FLOAT value);

我得到的编译器警告是:

876: C1000 (W) Illegal pointer assignment
876: C1024 (W) First operand of "=" is not lvalue

如果有人对我使用的编译器感兴趣,那就是日立处理器的瑞萨H8。

您可以使用以下修改代码

FSTtimePointer =(UINT8 *)&FSTtime;

您确定这是您要存储时间的方式吗? 浮点数据类型的内部通常不按字节屏障对齐,并且日期通常是从纪元开始的秒或毫秒(通常为UINT32UINT64 ),而不是浮点类型。 您可能还需要考虑处理器中MSB或LSB字节的顺序。 (免责声明:我不知道日立处理器如何处理字节顺序或浮点数据类型。)

如果确定这是您想要的方式,则应该能够使用union来寻址较大数据类型中的各个字节:

union converter_type
{
    UNIT8 elements[4];
    FLOAT whole;
} converter;

UINT8 time[6];
FLOAT FSTtime = 0;    //32bit float

//Get the current time as 6 bytes {secs,mins,hours,day,month,year}
returnSize = appP->DB_get_param_value(12, 0, 8, &time);
if (returnSize < 6) return;

//Pack 4 bytes of time data into a "float"
converter.elements[0] = time[3];  //Reverse month & day because Americans are backwards
converter.elements[1] = time[4];  // (Yes, we are.)
converter.elements[2] = time[2];  // (But what about Canadians? They're "American", too! ;) )
converter.elements[3] = time[1];
FSTtime = converter.whole;

appP->HIST_write_FST_log(SubMin_CFG.OFFSET, (UINT16)historyPointer, FSTtime);

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