如何使用beautifulsoup和python从此json提取数据？

Question

给定以下json，如何获取这两个值utc_last_updated和name？ 我使用请求来获取内容，然后使用BeautifulSoup使其像现在一样。 但是现在我只想提取我显示的两个值。

"data": [
        {
            "scm": "hg",
            "has_wiki": false,
            "last_updated": "2016-03-23T14:05:27.433",
            "no_forks": false,
            "created_on": "2016-03-18T22:55:52.705",
            "owner": "user",
            "email_mailinglist": "",
            "is_mq": false,
            "size": 420034,
            "read_only": false,
            "fork_of": null,
            "mq_of": null,
            "state": "available",
            "utc_created_on": "2016-03-18 21:55:52+00:00",
            "website": "",
            "description": "",
            "has_issues": false,
            "is_fork": false,
            "slug": "store",
            "is_private": true,
            "name": "store",
            "language": "python",
            "utc_last_updated": "2016-03-23 13:05:27+00:00",
            "no_public_forks": true,
            "creator": null,
            "resource_uri": "/1.0/repositories/my_url"
        },
        {
            "scm": "hg",
            "has_wiki": false,
            "last_updated": "2016-03-18T12:26:22.261",
            "no_forks": false,
            "created_on": "2016-03-18T12:19:08.262",
            "owner": "user",
            "email_mailinglist": "",
            "is_mq": false,
            "size": 173137,
            "read_only": false,
            "fork_of": null,
            "mq_of": null,
            "state": "available",
            "utc_created_on": "2016-03-18 11:19:08+00:00",
            "website": "",
            "description": "",
            "has_issues": false,
            "is_fork": false,
            "name": 'foo'
            "is_private": true,,
            "language": "python",
            "utc_last_updated": "2016-03-18 11:26:22+00:00",
            "no_public_forks": true,
            "creator": null,
            "resource_uri": "/1.0/repositories/my_rl"
        },

}我将不胜感激。

Answer 1

你已经有了一个JSON响应 ，而不是HTML -与解析它json模块 ：

import json

data = json.loads(response)
for item in data["data"]:
    print(item["utc_last_updated"])