[英]Join two tables with different column names and same rows
我有一张桌子:
|age | name | sex | money |
-------------------------------
|20 | James | 1 | 1000 |
|20 | Marry | 2 | 2000 |
|20 | Kate | 2 | 1500 |
|20 | Parker | 1 | 1800 |
我有两个查询结果:
1:
select `age`, count(*) as `man`, sum(money) as man_money
from table1
where `sex` = 1 and age = 20;
|age| man | man_money |
-------------------------
|20 | 2 | 2800 |
2:
select `age`, count(*) as `woman`, sum(money) as woman_money
from table1
where `sex` = 2 and age = 20;
|age |woman | woman_money |
-----------------------------
|20 |2 | 3500 |
我想合并结果,如:
|age | man | woman | man_money | woman_money |
--------------------------------------------------
|20 | 2 | 2 | 2800 | 3500 |
怎么写SQL?
尝试这个:
select age,
count(case when sex = 1 then 1 end) as man,
count(case when sex = 2 then 1 end) as woman,
sum(case when sex = 1 then money end) as man_money,
sum(case when sex = 2 then money end) as woman_money
from table1
where age = 20
我不了解Mysql,但是由于我对所有数据库的sql都一样,所以我在oracle中试了一下,可以根据需要工作
select age,
count(case when sex = 1 then 1 end) as man,
count(case when sex = 2 then 1 end) as woman
from table1 group by age;
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