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[英]How to perform complex query on aggregated fields in ElasticSearch
[英]ElasticSearch: Access outer document fields from within an nested aggregated query
我有以下映射:
{
"dynamic": "strict",
"properties": {
"id": {
"type": "string"
},
"title": {
"type": "string"
},
"things": {
"type": "nested",
"properties": {
"id": {
"type": "long"
},
"something": {
"type": "long"
}
}
}
}
}
我将文档插入如下(Python脚本):
body = {"id": 1, "title": "one", "things": [{"id": 1000, "something": 33}, {"id": 1001, "something": 34}, ]}
es.create(index_name, doc_type=doc_type, body=body, id=1)
body = {"id": 2, "title": "two", "things": [{"id": 1000, "something": 43}, {"id": 1001, "something": 44}, ]}
es.create(index_name, doc_type=doc_type, body=body, id=2)
body = {"id": 3, "title": "three", "things": [{"id": 1000, "something": 53}, {"id": 1001, "something": 54}, ]}
es.create(index_name, doc_type=doc_type, body=body, id=3)
我运行以下聚合查询:
{
"query": {
"match_all": {}
},
"aggs": {
"things": {
"aggs": {
"num_articles": {
"terms": {
"field": "things.id",
"size": 0
},
"aggs": {
"articles": {
"top_hits": {
"size": 50
}
}
}
}
},
"nested": {
"path": "things"
}
}
},
"size": 0
}
(因此,我希望计数每个“事物”出现的次数,并针对每个事物列出出现每个事物的文章列表)
查询产生:
"key": 1000,
"doc_count": 3,
"articles": {
"hits": {
"total": 3,
"max_score": 1,
"hits": [{
"_index": "test",
"_type": "article",
"_id": "2",
"_nested": {
"field": "things",
"offset": 0
},
"_score": 1,
"_source": {
"id": 1000,
"something": 43
}
}, {
"_index": "test",
"_type": "article",
"_id": "1",
"_nested": {
"field": "things",
"offset": 0
},
"_score": 1,
"_source": {
"id": 1000,
"something": 33
}
.... (等等)
我想要的是让每个匹配项列出“外部”或顶级文档中的所有字段,例如ID和标题。
这实际上可能吗...如果是这样的话???
我不确定这是否是您要寻找的东西,但让我们尝试一下:
{
"query": {
"match_all": {}
},
"aggs": {
"nested_things": {
"nested": {
"path": "things"
},
"aggs": {
"num_articles": {
"terms": {
"field": "things.id",
"size": 0
},
"aggs": {
"articles": {
"top_hits": {
"size": 50
}
},
"reverse_things": {
"reverse_nested": {},
"aggs": {
"title": {
"terms": {
"field": "title",
"size": 0
}
},
"id": {
"terms": {
"field": "id",
"size": 0
}
}
}
}
}
}
}
}
}
}
这将产生如下内容:
"buckets": [
{
"key": 1000,
"doc_count": 3,
"reverse_things": {
"doc_count": 3,
"id": {
"buckets": [
{
"key": "1",
"doc_count": 1
},
{
"key": "2",
"doc_count": 1
},
{
"key": "3",
"doc_count": 1
}
]
},
"title": {
...
}
},
"articles": {
"hits": {
"total": 3,
"max_score": 1,
"hits": [
{
"_index": "test",
"_type": "article",
"_id": "AVPOgQQjgDGxUAMojyuY",
"_nested": {
"field": "things",
"offset": 0
},
"_score": 1,
"_source": {
"id": 1000,
"something": 53
}
},
...
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