如何在Codeigniter中使用Join从两个表中获取价值

Question

public function user_data_vi($email)
{
    $this->db->select('*');
    $this->db->from('client');
    $this->db->join('payments', "payments.email = $email");

    $q= $this->db->get();

    return $q->result(); 
}

上面的代码是我的模型和方法user_data_vi我有两个表client并且两个表的email字段中都有另一个payments很常见，现在我想从数据库中检索数据第一个表有用户信息， payment table有付款信息获取信息两个表数据都使用email字段。

Answer 1

您需要在此处添加where条件，请在下面找到修改后的代码

public function user_data_vi($email)
{
        $this->db->select('*');
        $this->db->from('client');
        $this->db->join('payments', "payments.email = client.email");
        $this->db->where('client.email',$email);
        $q= $this->db->get();
        return $q->result(); 
}

Answer 2

public function user_data_vi($email)
{
    $this->db->select('*');
    $this->db->from('client');
    $this->db->where('client.email',$email);
    $this->db->join('payments','payments.email = client.email');
    $q= $this->db->get();
    return $q->result(); 

}