如何在Codeigniter中使用Join從兩個表中獲取價值

Question

public function user_data_vi($email)
{
    $this->db->select('*');
    $this->db->from('client');
    $this->db->join('payments', "payments.email = $email");

    $q= $this->db->get();

    return $q->result(); 
}

上面的代碼是我的模型和方法user_data_vi我有兩個表client並且兩個表的email字段中都有另一個payments很常見，現在我想從數據庫中檢索數據第一個表有用戶信息， payment table有付款信息獲取信息兩個表數據都使用email字段。

Answer 1

您需要在此處添加where條件，請在下面找到修改后的代碼

public function user_data_vi($email)
{
        $this->db->select('*');
        $this->db->from('client');
        $this->db->join('payments', "payments.email = client.email");
        $this->db->where('client.email',$email);
        $q= $this->db->get();
        return $q->result(); 
}

Answer 2

public function user_data_vi($email)
{
    $this->db->select('*');
    $this->db->from('client');
    $this->db->where('client.email',$email);
    $this->db->join('payments','payments.email = client.email');
    $q= $this->db->get();
    return $q->result(); 

}