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用“_”替换每个奇数出现的空格

[英]Replace every odd occurrence of space with “_”

我有以下字符串,我应该用_替换每个奇数出现的空格。

串:

901 R 902 M 903 Picture_message 904 NA 905 F 906 Local_Relay 907 46 
908 51705 909 306910001112/TYPE=PLMN@mms.cosmote.gr

预期字符串:

901_R 902_M 903_Picture_message 904_NA 905_F 906_Local_Relay 907_46 
908_51705 909_306910001112/TYPE=PLMN@mms.cosmote.gr

我尝试使用空间计数并使用正则表达式,但无法达到标记。

循环并保持找到的空格数但仅对奇数进行操作:

Dim thing: thing = "901 R 902 M 903 Picture_message 904 NA 905 F 906 Local_Relay 907 46 908 51705 909 306910001112/TYPE=PLMN@mms.cosmote.gr"
Dim i, counter

For i = 1 To Len(thing)
    If Mid(thing, i, 1) = " " Then
        counter = counter + 1
        If counter Mod 2 Then thing = Left(thing, i - 1) & "_" & Mid(thing, i + 1)
    End If
Next

msgbox thing

一种方法是在空格处拆分字符串,将下划线附加到奇数和空格到偶数元素(最后一个除外),然后将它们粘合在一起:

s = "901 R 902 M 903 Picture_message 904 NA 905 F 906 Loc..."

a = Split(s, " ")

For i = 0 To UBound(a)-1 Step 2
  a(i) = a(i) & "_"
Next
For i = 1 To UBound(a)-1 Step 2
  a(i) = a(i) & " "
Next

WScript.Echo Join(a, "")

如果你想避免循环两次,你可以像这样一次完成:

s = "901 R 902 M 903 Picture_message 904 NA 905 F 906 Loc..."

c = CreateObject("ScriptingDictionary")
c.Add 0, "_"
c.Add 1, " "

a = Split(s, " ")

For i = 0 To UBound(a)-1
  a(i) = a(i) & c(i Mod 2)
Next

WScript.Echo Join(a, "")

如果您仍想使用正则表达式

更新:改进了模式匹配,因此只检测到空白字符,因此如果数据包含902 R它仍将返回902_R

Dim data: data = "901 R 902 M 903 Picture_message 904 NA 905 F 906 Local_Relay 907 46 908 51705 909 306910001112/TYPE=PLMN@mms.cosmote.gr"
'Include value of first capture group (\b\d{3})
'and append _ to it, this will make up the replacement value.
Dim value: value = "$1_"
Dim result
Dim rx: Set rx = new RegExp

With rx
  .Global = True
  .IgnoreCase = True
  'Expression checks for word boundary followed by 3 digit value
  'followed by any number whitespace characters.
  .Pattern = "(\b\d{3})\s+"
  result = .Replace(data, value)
End With
Set rx = Nothing

WScript.Echo "--------- Test ----------"
WScript.Echo data
WScript.Echo result
WScript.Echo

输出:

--------- Test ----------
901 R 902 M 903 Picture_message 904 NA 905 F 906 Local_Relay 907 46 908 51705 909 306910001112/TYPE=PLMN@mms.cosmote.gr
901_R 902_M 903_Picture_message 904_NA 905_F 906_Local_Relay 907_46 908_51705 909_306910001112/TYPE=PLMN@mms.cosmote.gr

免责声明:我实际上错过了问题标题中的“奇怪”要求,这个例子只是使用模式匹配来查找样本数据<3 digit number><space>中的重复模式的出现,并将其Replace()与预期的<3 digit number><underscore>


性能注意事项

在侧面说明决定测试性能与经典的For循环方法,以显示为什么我切换到使用正则表达式这种类型的场景,使用@ alex-k的 示例构建了一个时序脚本,也允许我复制源数据多次创建更大的数据集。

复制源100次

RegEx Method
String Length: 11999
Start: 55250.37109375
Stop: 55250.40234375
Diff: 0.03125

For loop - Mod Method
String Length: 11999
Start: 55250.40234375
Stop: 55250.4375
Diff: 0.03515625

小幅增加1000倍

RegEx Method
String Length: 119999
Start: 55348.5859375
Stop: 55348.9375
Diff: 0.3515625

For loop - Mod Method
String Length: 119999
Start: 55348.9375
Stop: 55350.04296875
Diff: 1.10546875

但是看看如果我们把它增加到5000次会发生什么

RegEx Method
String Length: 599999
Start: 55545.69140625
Stop: 55547.4296875
Diff: 1.73828125

For loop - Mod Method
String Length: 599999
Start: 55547.4296875
Stop: 55584.15234375
Diff: 36.72265625

For循环方法的影响是指数级的,当我达到10000次RegEx方法运行时,然后在尝试运行For循环方法时无法及时返回。

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