最小最大日期列表之间的Oracle日期

Question

我有一张在不同日期吃过的鱼。

桌台：

Long ID, 
Long Vessel_id, -- vessel that is fishing 
TimeStamp fishing_date, 
double amount_cought
Long species_id;

接下来是一张使用船只捕鱼的公司表。

表ves_usage：

Long ID,
TimeStamp usage_start_date,
TimeStamp usage_end_date,
Long vessel_id,
Long using_company_id;

最后，我有一张在给定年份内为公司捕捞特定物种的许可证表。

餐桌牌照：

Long ID,
int year, --the year that the lincence is active
Long licenced_company_id,--company who was given the licence
Long species_id; --species that the company can fish

我正在尝试从着陆表中选择具有指定物种，公司和船只的所有记录。 我的问题是我想不出一种方法来选择ves_usage表记录的开始日期和结束日期之间的所有着陆记录。 不知道即时消息是否足够清晰：PI想做出类似的事情：

Select * 
from landings 
where fishing_date between <list of usage_start_date and usage_end_date from ves_usage table>

Answer 1

如果您希望查询基于ves_usage ID ，则此查询将起作用：

SELECT * 
FROM landings 
WHERE fishing_date BETWEEN
  (SELECT usage_start_date FROM ves_usage WHERE id = <id from ves_usage>)
  AND
  (SELECT usage_end_date FROM ves_usage WHERE id = <id from ves_usage>)

如果您希望有所不同，请根据评论中的要求进行指定。

Answer 2

如果我正确地遵循您的表，我相信查询将是这样的：

SELECT l.* 
FROM landings l
     JOIN ves_usage vu
          ON vu.vessel_id = l.Vessel_id
          AND l.fishing_date BETWEEN vu.usage_start_date AND vu.usage_end_date
     JOIN licences li
          ON li.vessel_id = vu.Vessel_id
          AND li.species = l.species_id
WHERE l.fishing_date = /*date here*/
      AND li.licenced_company_id = /*company id here*/