我正在尝试从需要登录但未获取任何数据的站点中抓取 HTML

Question

我正在关注本教程，但在运行 python 时似乎无法获取任何数据。 我得到一个 200 的 HTTP 状态代码， status.ok返回一个真值。 任何帮助都会很棒。 这就是我在终端中的响应：

[]

200

True

import requests
from lxml import html

USERNAME = "username@email.com"
PASSWORD = "legitpassword"

LOGIN_URL = "https://bitbucket.org/account/signin/?next=/"
URL = "https://bitbucket.org/dashboard/overview"

def main():
session_requests = requests.session()

# Get login csrf token
result = session_requests.get(LOGIN_URL)
tree = html.fromstring(result.text)
authenticity_token = list(set(tree.xpath("//input[@name='csrfmiddlewaretoken']/@value")))[0]

# Create payload
payload = {
    "username": USERNAME, 
    "password": PASSWORD, 
    "csrfmiddlewaretoken": authenticity_token
}

# Perform login
result = session_requests.post(LOGIN_URL, data = payload, headers = dict(referer = LOGIN_URL))

# Scrape url
result = session_requests.get(URL, headers = dict(referer = URL))
tree = html.fromstring(result.content)
bucket_elems = tree.findall(".//span[@class='repo-name']")
bucket_names = [bucket_elem.text_content().replace("\n", "").strip() for bucket_elem in bucket_elems]

print bucket_names
print result.status_code

if __name__ == '__main__':
main()

Answer 1

xpath 是错误的，类 repo-name 没有 span，您可以使用以下命令从锚标记中获取 repo 名称：

bucket_elems = tree.xpath("//a[@class='execute repo-list--repo-name']")
bucket_names = [bucket_elem.text_content().strip() for bucket_elem in bucket_elems]

自从编写教程以来，html 显然发生了变化。