在字典中，如何从具有多个值的键中删除一个值？ 蟒蛇

Question

from collections import OrderedDict

def main():
    dictionary = OrderedDict()
    dictionary["one"] = ["hello", "blowing"]
    dictionary["two"] = ["frying", "goodbye"]

    for key in dictionary:
        print key, dictionary[key]

    user_input = raw_input("REMOVE BUILDINGS ENDING WITH ING? Y/N")
    if user_input == ("y"):
        print ""
        for key in dictionary:
            for x in dictionary[key]:
                if ("ING") in x or ("ing") in x:
                    del dictionary[key][x]

    print ""

    for key in dictionary:
        print key, dictionary[key]

main()

我正在尝试从字典中的所有键中删除其中带有“ ing”的任何项目，例如，从键“ one”中删除“ blowing”，从键“ two”中删除“ frying”。

产生的字典将来自此：

one ['hello', 'blowing'], two ['frying', 'goodbye']

对此：

one ['hello'], two ['goodbye']

Answer 1

字典理解。

return {x : [i for i in dictionary[x] if not i.lower().endswith('ing')] for x in dictionary}

编辑以将“ ing”结尾的值替换为“ removed”

return {x : [i if not i.lower().endswith('ing') else 'removed' for i in dictionary[x]] for x in dictionary}

Answer 2

您可以通过使用dict理解以不可变的方式（即，不改变原始dict）来做到这一点：

>>> d = {'one': ['hello', 'blowing'], 'two': ['frying', 'goodbye']}
>>> {k: [w for w in v if not w.lower().endswith('ing')] for k, v in d.items()}
{'one': ['hello'], 'two': ['goodbye']}

Answer 3

尝试这个：

>>> collections.OrderedDict({key:filter(lambda x:not x.endswith('ing'), value) for key,value in dictionary.items()})
OrderedDict([('two', ['goodbye']), ('one', ['hello'])])

Answer 4

{key: [ele for ele in val if not ele.lower().endswith('ing')] for key, val in d.items()}

说明：

从右边开始

• d是字典，它存储<key, [val]>

• 对于d每个key, val我们执行以下操作，

• [ele for ele in val if not ele.lower().endswith('ing')]表示对于list（ val ）中的每个元素（ ele ），我们执行以下操作：

  • 将每个字符串转换为小写
  • 检查它是否以-ing结尾
  • 然后如果这些都不是（ if not ），则得到ele

• 然后，您只需打印{ key: [ele1, ele2, ..] , .. } 。

Answer 5

您试图删除的字符串索引不是int位置参考。 这是修改后的代码：

from collections import OrderedDict

def main():
    dictionary = OrderedDict()
    dictionary["one"] = ["hello", "blowing"]
    dictionary["two"] = ["frying", "goodbye"]

    for key in dictionary:
        print key, dictionary[key]

    user_input = raw_input("REMOVE BUILDINGS ENDING WITH ING? Y/N")
    if user_input == ("y"):
        print ""
        for key,value in dictionary.iteritems():
            for i,x  in enumerate(value):
                if ("ING") in x or ("ing") in x:
                    del dictionary[key][i]

    print ""

    for key in dictionary:
        print key, dictionary[key]

main()