如何快速获取类型字典数组的键

Question

如何快速获取字典类型数组的键。 我希望输出为location1，location2，location3（类型为dictionary的数据数组的键）

//我的代码如下

 class ViewController: UIViewController 
        {
        var data = [NSDictionary]()

            var LocationPickerData:[String] = ["Mozzarella","Gorgonzola","Provolone","Brie","Maytag Blue","Sharp Cheddar","Monterrey Jack","Stilton","Gouda","Goat Cheese", "Asiago"]

            var LocationPickerData2 = ["Mozzarella","Gorgonzola","Provolone","Brie","Maytag Blue","Sharp Cheddar","Monterrey Jack","Stilton","Gouda","Goat Cheese", "Asiago"]

            var LocationPickerData3 = ["Mozzarella","Gorgonzola","Provolone","Brie","Maytag Blue","Sharp Cheddar","Monterrey Jack","Stilton","Gouda","Goat Cheese", "Asiago"]

     override func viewDidLoad() {
                super.viewDidLoad()
             data = [["lacation1":LocationPickerData],["location2":LocationPickerData2],["location2":LocationPickerData3]]

print(data[keys])

        }
        }

Answer 1

在您的情况下，您将必须遍历data并且在每次迭代中都将获取数组中第一个对象的键。 那是因为它是Dictionaries Array ，而不是Dictionary 。 但是，我建议将您的data变量构造为Dictionary ，除非您的解决方案有更多内容，否则没有理由不这样做。

我建议执行以下操作：

data = ["location1":LocationPickerData, "location2":LocationPickerData2, "location3":LocationPickerData3]

然后，获取密钥很简单：

data.keys

注意： Dictionary不会排序。