使用 flask_pymongo 时身份验证失败

Question

我确信 MONGO_URI 是正确的，因为它在 pymongo 中运行良好。 但是当使用flask_pymongo时，它不起作用......这是我的测试代码：

from flask import Flask
from flask_pymongo import PyMongo
app = Flask(__name__)

app.config['MONGO_URI'] ='mongodb://root:aaa2016@localhost:27017/mongo_test'
mongo = PyMongo(app, config_prefix='MONGO')


@app.route('/')
def hello_world():
    mongo.db.user.insert({'username': "aaa"})
    return 'Hello World!'


if __name__ == '__main__':
    app.run()

运行它并访问 127.0.0.1:5000，给出 500 的响应。

OperationFailure: Authentication failed.
127.0.0.1 - - [21/Jun/2016 20:40:25] "GET / HTTP/1.1" 500 -

任何帮助将不胜感激。

更新：这是回溯：

File "C:\Python27\lib\site-packages\flask\app.py", line 2000, in __call__
return self.wsgi_app(environ, start_response)
File "C:\Python27\lib\site-packages\flask\app.py", line 1991, in wsgi_app
response = self.make_response(self.handle_exception(e))
File "C:\Python27\lib\site-packages\flask\app.py", line 1567, in       handle_exception
reraise(exc_type, exc_value, tb)
File "C:\Python27\lib\site-packages\flask\app.py", line 1988, in wsgi_app
response = self.full_dispatch_request()
File "C:\Python27\lib\site-packages\flask\app.py", line 1641, in  full_dispatch_request
rv = self.handle_user_exception(e)
File "C:\Python27\lib\site-packages\flask\app.py", line 1544, in handle_user_exception
reraise(exc_type, exc_value, tb)
File "C:\Python27\lib\site-packages\flask\app.py", line 1639, in full_dispatch_request
rv = self.dispatch_request()
File "C:\Python27\lib\site-packages\flask\app.py", line 1625, in dispatch_request
return self.view_functions[rule.endpoint](**req.view_args)
File "F:\PycharmProjects\flask_\flask_.py", line 12, in hello_world
mongo.db.user.insert({'username': "aaa"})
File "C:\Python27\lib\site-packages\pymongo\collection.py", line 2203, in insert
with self._socket_for_writes() as sock_info:
File "C:\Python27\lib\contextlib.py", line 17, in __enter__
return self.gen.next()
File "C:\Python27\lib\site-packages\pymongo\mongo_client.py", line 718, in _get_socket
with server.get_socket(self.__all_credentials) as sock_info:
File "C:\Python27\lib\contextlib.py", line 17, in __enter__
return self.gen.next()
File "C:\Python27\lib\site-packages\pymongo\server.py", line 152, in get_socket
with self.pool.get_socket(all_credentials, checkout) as sock_info:
File "C:\Python27\lib\contextlib.py", line 17, in __enter__
return self.gen.next()
File "C:\Python27\lib\site-packages\pymongo\pool.py", line 541, in get_socket
sock_info.check_auth(all_credentials)
File "C:\Python27\lib\site-packages\pymongo\pool.py", line 306, in  check_auth
auth.authenticate(credentials, self)
File "C:\Python27\lib\site-packages\pymongo\auth.py", line 436, in authenticate
auth_func(credentials, sock_info)
File "C:\Python27\lib\site-packages\pymongo\auth.py", line 416, in _authenticate_default
return _authenticate_scram_sha1(credentials, sock_info)
File "C:\Python27\lib\site-packages\pymongo\auth.py", line 188, in _authenticate_scram_sha1
res = sock_info.command(source, cmd)
File "C:\Python27\lib\site-packages\pymongo\pool.py", line 213, in command
read_concern)
File "C:\Python27\lib\site-packages\pymongo\network.py", line 99, in command
helpers._check_command_response(response_doc, None, allowable_errors)
File "C:\Python27\lib\site-packages\pymongo\helpers.py", line 196, in _check_command_response
raise OperationFailure(msg % errmsg, code, response)
OperationFailure: Authentication failed.

Answer 1

这个问题可能很老，但我遇到了同样的问题，并找到了另一个可能适用于其他人的解决方案。

将?authSource=admin附加到MONGO_URI变量的末尾将根据管理数据库验证您的凭据，而不是您正在连接的数据库。

示例： app.config["MONGO_URI"] = "mongodb://username:password@host:port/db_name?authSource=admin"

Answer 2

问题是，如果您使用MONGO_URI配置参数，那么 pymongo 会尝试针对字符串中包含的数据库名称进行身份验证。 您应该将配置参数分解为以下内容，以便您可以指定数据库名称和身份验证源。

app.config['MONGO_HOST'] = 'localhost'
app.config['MONGO_PORT'] = '27017'
app.config['MONGO_DBNAME'] = 'mongo_test'
app.config['MONGO_USERNAME'] = 'root'
app.config['MONGO_PASSWORD'] = 'aaa2016'
app.config['MONGO_AUTH_SOURCE'] = 'admin' . # root user is typically defined in admin db

Answer 3

如果您使用Flask-MongoEngine并使用app.config['MONGODB_*']设置 mongo 配置，那么您的 uri 将从这些变量生成，例如

app.config['MONGODB_DB'] = 'project1'
app.config['MONGODB_HOST'] = '192.168.1.35'
app.config['MONGODB_PORT'] = 12345
app.config['MONGODB_USERNAME'] = 'webapp'
app.config['MONGODB_PASSWORD'] = 'pwd123'

但是，如果您需要向 uri 添加一些额外的参数（例如查询参数authSource=admin ），则必须通过app.config['MONGODB_SETTINGS']传递 mongo 配置

app.config['MONGODB_SETTINGS'] = {
    'connect': False,
    'host': 'mongodb://webapp:pwd123@192.168.1.35:12345/project1?authSource=admin'
}

Answer 4

这几乎就是使用flask_pymongo对我有用的东西：

from flask import Flask
from flask_pymongo import PyMongo

app = Flask(__name__)
app.config['MONGO_URI']='mongodb://appUser:passwordForAppUser@localhost/app_db?authSource=admin'

mongo=PyMongo(app)

或者您也可以尝试使用 MongoEngine 代替这个其他示例：

from flask import Flask
from flask_mongoengine import MongoEngine
    
app = Flask(__name__)
app.config['MONGODB_SETTINGS'] = {
        'db': 'app_db',
        'host': 'localhost',
        'port': 27017,
        'username': 'appUser',
        'password': 'passwordForAppUser',
        'authentication_source': 'admin'
}

db = MongoEngine(app)