找不到页面（404）

Question

我正在做一个可能有详细视图的简单的公司评估应用程序。 而列表视图正常显示，每当我单击以查看其详细信息时，我都会得到页面未找到（404）错误。 它的工作原理是，如果您要单击部门（列表视图），则必须将您带到显示徽标的详细页面，并在该部门下发布。

追溯;

Page not found (404)
Request Method: GET
Request URL:    http://127.0.0.1:8000/1//
Using the URLconf defined in Employee.urls, Django tried these URL patterns, in this order:
^admin/
^appraisal/
^ ^$ [name='index']
^ ^(?P<pk>[0-9]+)/$ [name='detail']
^static\/(?P<path>.*)$
^media\/(?P<path>.*)$
The current URL, 1//, didn't match any of these.

我的看法；

from django.views import generic
from .models import Department

class IndexView(generic.ListView):
    template_name = "index.html"
    context_object_name = "departments"

    def get_queryset(self):
        return Department.objects.all()


class DetailView(generic.DetailView):
    model = Department
    template_name = "detail.html"

我的网址；

项目/网址

from django.conf.urls import include, url
from django.contrib import admin
from django.conf import settings
from django.conf.urls.static import static

urlpatterns = [
    url(r'^admin/', include(admin.site.urls)),
    url(r'^appraisal/', include('Appraisal.urls')),
    url(r'^', include('Appraisal.urls')),
]
if settings.DEBUG:
    urlpatterns += static(settings.STATIC_URL, document_root=settings.STATIC_ROOT)
    urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)

应用/网址；

from django.conf.urls import url
from . import views

app_name = 'Appraisal'

urlpatterns = [
    url(r'^$', views.IndexView.as_view(), name='index'),
    url(r'^(?P<pk>[0-9]+)/$', views.DetailView.as_view(), name='detail'),
]

我的模特

class Department(models.Model):
    Name = models.CharField(max_length=30)
    Leader = models.ForeignKey(Employee)
    Department_logo = models.FileField()
    is_favorite = models.BooleanField(default=False)

    def __str__(self):
        return '{}'.format(self.Name)


class Post(models.Model):
    Title = models.CharField(max_length=30)
    Department = models.ForeignKey(Department, on_delete=models.CASCADE)
    is_favorite = models.BooleanField(default=False)

    def __str__(self):
        return '{}'.format(self.Title)

有人帮助我解决了这个问题，我知道这确实是一件很小的事情，导致它无法正常工作。 谢谢！！

Answer 1

您的链接越野车http://127.0.0.1:8000/1//一个斜杠太多

网址必须正确为http://127.0.0.1:8000/1/或http://127.0.0.1:8000/

您可能在模板中建立了错误的链接。