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[英]Can't compile console app, using QPFloat, a 128-bit floating-point library
[英]Can't increment value of a floating-point variable
我是C#的新手,我无法理解,为什么我的变量不想增加到大于16777215的值。
我有代码:
float fullPerc = 100;
float bytesRead = 1;
long fileSize = 1;
ProgressBar pb1;
int blockSizeBytes = 0;
float counter = 0;
using (FileStream inFs = new FileStream(inFile, FileMode.Open))
{
fileSize = inFs.Length;
do
{
counter = counter + 1;
if (counter > 16777215) //&& counter < 16777230)
{
counter = counter + 10;
//Console.WriteLine(((counter + 10) /100));
}
count = inFs.Read(data, 0, blockSizeBytes);
offset += count;
outStreamEncrypted.Write(data, 0, count);
bytesRead += blockSizeBytes;
}
while (count > 0);
inFs.Close();
}
当计数器的值等于16777216时,可变增量counter = counter + 1;
代码counter = counter + 1;
不起作用,但是这段代码
if (counter > 16777215) //&& counter < 16777230)
{
counter = counter + 10;
//Console.WriteLine(((counter + 10) /100));
}
很好。
即,如果我if
代码中对此注释,则我的counter
将增长到16777216的值并将停止在该值上。 当此变量> = 16777216时,仅将其递增10即可。
为什么?
您的尾数溢出 ,结果是精度损失 。 float
(或Single
)类型的尾数为24位(最多16777216
):
https://en.wikipedia.org/wiki/Single-precision_floating-point_format
让我们看看发生了什么:
private static String MakeReport(float value) {
return String.Join(" ", BitConverter
.GetBytes(value)
.Select(b => Convert.ToString(b, 2).PadLeft(8, '0')));
}
...
float f = 16777215;
// Mantissa (first 3 bytes) is full of 1's except the last one bit
// 11111111 11111111 01111111 01001011
Console.Write(MakeReport(f));
// Overflow! Presision loss
// 00000000 00000000 10000000 01001011
Console.Write(MakeReport(f + 1));
// Overflow! Presision loss
// 00000000 00000000 10000000 01001011
Console.Write(MakeReport(f + 2));
// Overflow! Presision loss
// 00000100 00000000 10000000 01001011
Console.Write(MakeReport(f + 10));
补救措施:不要将浮点数用作counter
而应使用整数 :
int counter = 0;
避免整数除法将值转换为double
float x = (float) ((((double)counter * blockSizeBytes) / fileSize) * fullPerc);
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