[英]PHP - where clause equals 2 values grabbed from URL is not showing any results?
[英]Getting multiple results from WHERE clause in PHP
请原谅我可怕的编码和设计方面。 我并不太关心它的外观,因为我的工作效果如何。
我有2个表(汽车,客户),其中两个都有VIN列。 当我添加一辆新车时,我放入了VIN,当客户购买车辆时,我从所有车辆中填充的下拉列表中选择VIN,并将字段VSold设置为“N”。 这很好用,我的问题是,当我运行下面的代码时,它给了我多个客户名称。 当我在该数据库中为该表和精确的VIN运行搜索查询时,只有一个客户具有匹配的VIN(我使其成为独一无二的),但在我丑陋的代码中,它给了我一堆结果,都是一样的汽车,只是不同的客户。 我在这做错了什么? 我怎样才能清理这个东西?
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(! $conn ) {
die('Could not connect: ' . mysql_error());
}
$VIN=$_POST['formVIN'];
$sql =
"SELECT
Cars.VIN, Cars.VYear, Cars.VMake, Cars.VModel,
Cars.VOdometer, Cars.VPurchasedPrice, Cars.VPurchasedDate,
Cars.VSold, Cars.VSoldPrice, Cars.VSoldDate, Cars.VSalesPerson,
Customers.CustFirst, Customers.CustLast
FROM
Cars, Customers
WHERE Cars.VIN='$VIN'";
mysql_select_db('dbCar2016');
$retval = mysql_query( $sql, $conn );
if(! $retval ) {
die('Could not get data: ' . mysql_error());
}
while($row = mysql_fetch_array($retval, MYSQL_ASSOC)) {
echo "Information on record for the VIN provided:<br><br>";
echo "VIN:" . $row["VIN"] . "<br>";
echo "Year:" . $row["VYear"] . "<br>";
echo "Make:" . $row["VMake"] . "<br>";
echo "Model:" . $row["VModel"] . "<br>";
echo "Odometer:" . $row["VOdometer"] . "<br>";
echo "Purchased Price:$" . $row["VPurchasedPrice"] . "<br>";
echo "Purchased Date:" . $row["VPurchasedDate"] . "<br><br>";
if ($row["VSold"]=='Y') {
echo "This Vehicle sold.<br>";
echo "Price Sold:" . $row["VSoldPrice"] . "<br>";
echo "Date Sold:" . $row["VSoldDate"] . "<br>";
echo "Sales Person:" . $row["VSalesPerson"] . "<br><br>";
echo "It was sold to<br>";
echo "Customer Name:" . $row["CustFirst"] . " " . $row["CustLast"] . "<br>";
} else {
echo "This Vehicle has not sold yet.<br>";
}
echo "<p>VIN Successfully Searched</p>";
}
echo "<a href=vinlookup.php>Search Another VIN</a>";
mysql_close($conn);
?>
当我把未售出的车辆的VIN(VSold ='N')时,我没有任何问题。 (我想......)我尝试在桌子之间使用UNION,但我更加混乱了。
提前谢谢你的帮助!
更新:
UPDATE
Cars SET VSold='Y',
VSoldPrice='$VSoldPrice',
VSoldDate='$CustDownDate',
VSalesPerson='$VSalesPerson'
WHERE
VIN='$VIN'
是我在页面上添加客户的内容。 它将所有客户信息(CustFirst,CustLast等)输入到客户表中。 因此,如果没有客户与任何VIN(Cars.VIN)相关联,则不会填写Customers.VIN。
如果我正确理解了您的问题(您有多个查询返回而不仅仅是一个),请更改此:
WHERE Cars.VIN='$VIN'
对此
WHERE Cars.VIN='$VIN' AND Cars.VIN = Customers.VIN
从你想要做的事情来看,你应该使用内部来从两个表中获取信息。
SELECT Cars.VIN, Cars.VYear, Cars.VMake, Cars.VModel, Cars.VOdometer, Cars.VPurchasedPrice, Cars.VPurchasedDate, Cars.VSold, Cars.VSoldPrice, Cars.VSoldDate, Cars.VSalesPerson, Customers.CustFirst, Customers.CustLast
FROM Cars
INNER JOIN Customers
ON Customers.vin = Cars.vin
WHERE Cars.VIN='$VIN'";
SELECT
Cars.VIN, Cars.VYear, Cars.VMake, Cars.VModel, Cars.VOdometer,
Cars.VPurchasedPrice, Cars.VPurchasedDate, Cars.VSold, Cars.VSoldPrice,
Cars.VSoldDate, Cars.VSalesPerson, Customers.CustFirst, Customers.CustLast
FROM
Cars, Customers
WHERE
Cars.VIN='$VIN'
在cars
和customers
之间生产笛卡尔积 。 也就是说,它返回两个表之间的所有行组合。 为避免这种情况,您需要加入。 如果每个客户总是至少有一辆售出的汽车(即,它是销售数据库),那么使用inner join
。 但是,如果您的客户有时没有购买汽车,但仍然想要所有客户,那么请使用left join
。 如果没有相应的记录,这将导致所有car列包含NULL
。
SELECT
Cars.VIN, Cars.VYear, Cars.VMake, Cars.VModel, Cars.VOdometer,
Cars.VPurchasedPrice, Cars.VPurchasedDate, Cars.VSold, Cars.VSoldPrice,
Cars.VSoldDate, Cars.VSalesPerson, Customers.CustFirst, Customers.CustLast
FROM
Cars
LEFT JOIN Customers on Cars.VIN = Customers.VIN
WHERE
Cars.VIN='$VIN'
另外,请查看使用mysqli库(或类似文件)并了解如何参数化查询,以便以后可以避免处理SQL注入 。
虽然您的所有答案都解决了多个搜索结果,但如果车辆未售出则没有给我任何结果,因此没有与任何客户相关的VIN。 我决定通过多个搜索查询和IF语句来解决这个问题。 可能不是最有效或最清洁,但效果很好。 任何代码改进都是受欢迎的。 感谢你们所有人的帮助!
$formVIN = $_POST[formVIN]
sql1= SELECT * FROM Cars WHERE VIN=$formVIN
sql2= SELECT * FROM Customers WHERE VIN=$formVIN
$retval1=mysql_query( $sql1, $conn )
$retval2=mysql_query( $sql2, $conn )
if(! $retval1 ) {
die('No VIN information.' . mysql_error());
} else {
while($row1 = mysql_fetch_array($retval1, MYSQL_ASSOC)) {
echo "<p><b>Information on record for the VIN provided:</b></p>";
echo "VIN:" . $row1["VIN"] . "<br>";
echo "Year:" . $row1["VYear"] . "<br>";
echo "Make:" . $row1["VMake"] . "<br>";
echo "Model:" . $row1["VModel"] . "<br>";
if ($row1["VSold"]=='Y')
{
while($row2 = mysql_fetch_array($retval2, MYSQL_ASSOC)) {
echo "<p><b>This Vehicle sold.</b></p>";
echo "Price Sold:" . $row1["VSoldPrice"] . "<br>";
echo "Date Sold:" . $row1["VSoldDate"] . "<br>";
echo "Sales Person:" . $row1["VSalesPerson"] . "<br>";
echo "<p><b>It was sold to:</b></p>";
echo "Customer ID:" . $row2["CustID"] . "<br>";
echo "Customer Name:" . $row2["CustFirst"] . " " . $rowl["CustLast"] . "<br>";
}
} else
{
echo "<p><b>This Vehicle has not sold yet.</b></p><br>";
}
}
}
就像我说的那样,可能不是最有效的方法,但效果很好。 感谢大家!
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