将值绑定到字典中的键，然后打印

Question

这是我编写的主要代码的一小部分。 根据用户的选择，他们可以添加播放器信息a，然后从字典播放器名册中打印信息。 我想存储信息，然后以这种格式打印，但是我无法弄清楚该怎么做。 姓名****电话号码****泽西岛号码****我是词典的新手，但过去几天我花了数小时阅读和搜索有关词典的信息，并尝试了几种不同的方法来完成此操作但失败了。 我已经以现在的方式获得了最接近的设置，但仍然无法正常工作。 我觉得我将信息错误地存储在字典中供初学者使用，对您的帮助将不胜感激。

player_roster = {}
def display_roster(self):                         #Print Roster
    if len(player_roster) != 0:
        for x in player_roster.keys():
            print('Name:', x, 'Phone Number:', player_roster[x])
    else:                                          #Print No One on Roster
        len(player_roster) == []
        print('No names have been entered:')

def add_player(self,):                              #Enter Members Name
    name = input('Enter New Players Name:')
    phone_number = input('Enter Players Phone Number:')
    jersey_number = int(input('Enter Players Jersey Number'))
    player_roster[name] = phone_number, 'Jersey Number', jersey_number
#If I input Toby as Name 444-444 as Phone Number and 3 as Jersey number it outputs like this
Name: Toby Phone Number: ('444-4444', 'Jersey Number', 3)
# I would like it to output like 
                                 Name: Toby
                                 Phone Number: 444-4444
                                 Jersey Number: 3

Answer 1

有一些事情我会在您的代码中进行更改，但为了使其与您的要求保持一致，请看一下以下内容：

def display_roster():
    if len(player_roster) != 0:
        for x in player_roster.keys():
            print('Name:', x)
            print('Phone Number:', player_roster[x][0])
            print('Jersey Number:', player_roster[x][1])
    else:
        print('Roster is empty.')
    return


player_roster = {}
def add_player():
    name = input('Enter New Players Name:\t')
    phone_number = input('Enter Players Phone Number:\t')
    jersey_number = int(input('Enter Players Jersey Number:\t'))
    player_roster[name] = [phone_number, jersey_number]
    return

add_player()
display_roster()

# PRINTS:
#Name: Toby
#Phone Number: 444-4444
#Jersey Number: 3

多行打印可为您提供所需的结果。 如评论中所述，这也可以使用单个print()语句完成，但我认为紧凑的代码对您没有多大影响。

此外，此len(self.player_roster) == []行没有意义。 这与简单地在一行中编写True一样好。 团队的“空虚”由else:检查else: 。

最后，我会稍微改变玩家在“ Roster”字典中的存储方式，并使其如下： {"Toby": ['444-4444', 3], ...}

Answer 2

你几乎在那里。 下面的修改将允许您根据需要进行打印（并且可读性更高）：

class PlayerDictionary():
    def __init__(self):
        pass
    player_roster = {}
    def display_roster(self):                         #Print Roster
        if len(self.player_roster) != 0:
            for key, value in self.player_roster.iteritems():
                print(str(key) + ": " + str(value))
        else:                                          #Print No One on Roster
            len(self.player_roster) == []
            print('No names have been entered:')

    def add_player(self,):
        self.player_roster['Name'] = input('Enter New Players Name:')
        self.player_roster['Phone Number'] = input('Enter Players Phone Number:')
        self.player_roster['Jersey Number'] = int(input('Enter Players Jersey Number'))

if __name__ == "__main__":
    player = PlayerDictionary()
    player.add_player()
    player.display_roster()

一个稍微更可维护的解决方案是为Player创建一个类。 在对象上设置属性并重载str函数，例如

class Player(object):
    def __init__(self):
        self.__name = ""
        self.__phone_number = ""
        self.__jersey_number = ""

    @property
    def name(self):
        return self.__name

    @property
    def phone_number(self):
        return self.__phone_number

    @property
    def jersey_number(self):
        return self.__jersey_number

    @name.setter
    def name(self, val):
        self.__name = val

    @phone_number.setter
    def phone_number(self, val):
        self.__phone_number = val

    @jersey_number.setter
    def jersey_number(self, val):
        self.__jersey_number = val

    def __str__(self):
        return ("Name: %s\nPhone Number: %s\nJersey Number: %s" % (str(self.__name), str(self.__phone_number), str(self.__jersey_number)))

if __name__ == "__main__":
    player = Player()
    player.name = input('Enter New Players Name:')
    player.phone_number = input('Enter Players Phone Number:')
    player.jersey_number = int(input('Enter Players Jersey Number'))
    print(player)

Answer 3

我建议您将打印语句替换为：

print(" Name: %s \n Phone Number: %s \n Jersey Number: %d") % player_roster[x]