如何基于数组中的预定义值拆分字符串

Question

我想基于一开始就定义为常量的数组拆分字符串：

class Query
  OPERATOR = [':','=','<','>','<=','>=']
  def initialize(params)
    #Here i want to split given params if it contains any
    #of the operators from OPERATOR     
  end
end

Query.new(["Status<=xyz","Org=abc"])

我怎样才能做到这一点？

Answer 1

OPERATOR = ['<=','=>',':','=','<','>']

r = /\s*#{ Regexp.union(OPERATOR) }\s*/
  #=> /\s*(?-mix:<=|=>|:|=|<|>)\s*/

str = "Now: is the =time for all <= to =>"

str.split(r)
  #=> ["Now", "is the", "time for all", "to"] 

请注意，我对OPERATOR的元素进行了重新排序，以使'<='和'=>' （每个元素由数组中两个长度为1的字符串组成）位于开头。 如果不这样做，

OPERATOR = [':','=','<','>','<=','>=']
r = /\s*#{ Regexp.union(OPERATOR) }\s*/
  #=> /\s*(?-mix::|=|<|>|<=|>=)\s*/ 
str.split(r)
  #=> ["Now", "is the", "time for all", "", "to"] 

str.split(r)

参见Regexp :: union 。