[英]Django simple queryset in form field
我在以前的答案中找不到任何解决方案,所以我在这里问如何注册由queryset生成的表单字段的结果。 也许我在这里做错了一些简单的事情,无论我的模型如何:
@python_2_unicode_compatible
class Choice(models.Model):
choice_text = models.CharField(max_length=100)
def __str__(self):
return self.choice_text
@python_2_unicode_compatible
class Contatto(models.Model):
contatto_choice = models.ForeignKey(Choice, on_delete=models.PROTECT)
phone_number = models.CharField(max_length=12)
email = models.CharField(max_length=100)
text = models.CharField(max_length=250)
def __str__(self):
return self.email
class ContactForm(ModelForm):
class Meta:
model = Contatto
fields = ['contatto_choice', 'phone_number','email','text']
我的forms.py是:
class ContactForm(forms.Form):
contatto_choice = forms.ModelChoiceField(queryset=Choice.objects.all())
phone_number = forms.CharField(max_length=12)
email = forms.CharField(max_length=100)
text = forms.CharField(widget=forms.Textarea, max_length=500)
我的看法是:
def contatti(request):
if request.method=="POST":
form = ContactForm(request.POST)
if form.is_valid():
contatto = Contatto()
contatto.phone_number = form.cleaned_data['phone_number']
contatto.email = form.cleaned_data['email']
contatto.text = form.cleaned_data['text']
contatto.contatto_choice = form.cleaned_data['contatto_choice']
contatto.save()
recipients = ['cercaservizi@gmail.com']
send_mail("Contatto Cercaservizi", contatto.phone_number+' '+contatto.email+' '+contatto.text,contatto.email, recipients)
return HttpResponseRedirect('/')
else:
form = ContactForm()
return render(request, 'form.html', {'form': form})
提交的表单的视图抱怨contatto_choice应该是选择的一个实例,我找不到任何有关如何解决此问题的教程。 如果您可以帮助,将不胜感激。
编辑您的联系表
class ContactForm(ModelForm):
contatto_choice = forms.ModelChoiceField(queryset=Choice.objects.all())
class Meta:
model = Contatto
fields = ['contatto_choice', 'phone_number','email','text']
而且您不需要其他形式
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