在Swift 2中将JSON转换为数组

Question

我需要为Grouped UITableView构建Arrays ，每个表格单元格中都有一个Title和Detail行。 我从服务器获得了json输出，使其形状正确，以迭代UITableViewDataSource方法。 但是将这些转换为UITableView函数可以引用的可UITableView组的最简单方法是什么？

标题数组用于组标题，因此它只是一维数组。 我可以迭代一下。 标题和细节数组都是二维的。 我无法弄清楚如何在Swift中做到这一点。

"headings":["Tuesday, August 16, 2016","Wednesday, August 17, 2016","Thursday, August 18, 2016","Friday, August 19, 2016","Saturday, August 20, 2016","Sunday, August 21, 2016","Monday, August 22, 2016","Tuesday, August 23, 2016","Wednesday, August 24, 2016","Thursday, August 25, 2016","Friday, August 26, 2016","Saturday, August 27, 2016","Sunday, August 28, 2016","Monday, August 29, 2016","Tuesday, August 30, 2016","Wednesday, August 31, 2016","Thursday, September 1, 2016","Friday, September 2, 2016","Saturday, September 3, 2016","Sunday, September 4, 2016","Monday, September 5, 2016","Tuesday, September 6, 2016","Wednesday, September 7, 2016","Thursday, September 8, 2016","Friday, September 9, 2016","Saturday, September 10, 2016","Sunday, September 11, 2016","Monday, September 12, 2016","Tuesday, September 13, 2016","Wednesday, September 14, 2016","Thursday, September 15, 2016","Friday, September 16, 2016"],

"titles":[["Joe Johnson"],["Joe Johnson"],["Sandy Primmell","Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Sandy Primmell","Joe Johnson"],["Joe Johnson","Joe Johnson"],["Sandy Primmell","Joe Johnson"],["Mark Greene","Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Sandy Primmell","Joe Johnson"],["Joe Johnson"],["Sandy Primmell","Joe Johnson"],["Mark Greene","Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"],["Joe Johnson"]],

"details":[["OFF"],["OFF"],["Gregory","OFF"],["Gregory"],["OFF"],["OFF"],["OFF"],["Weekday Rounders","OFF"],["Weekday Rounders","Night Owls"],["Gregory","OFF"],["Gregory","OFF"],["OFF"],["OFF"],["OFF"],["Gregory"],["Gregory","OFF"],["Gregory"],["Gregory","OFF"],["Gregory","OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"],["OFF"]]

UPDATE

这是抓取数据的Alamofire异步函数：

manager.request(.POST, getRouter(), parameters:["dev": 1, "app_action": "schedule", "type":getScheduleType(), "days_off":getScheduleDaysOff(), "period":getSchedulePeriod(), "begin_date":getScheduleBeginDate(), "end_date":getScheduleEndDate()])
        .responseString {response in
            print(response)
            var json = JSON(response.result.value!);
// what I'm missing
   }

Answer 1

你可以使用这个功能：

func convertStringToDictionary(text: String) -> [String:AnyObject]? {
    if let data = text.dataUsingEncodi‌​ng(NSUTF8StringEncodi‌​ng) {
        do {
            return try NSJSONSerialization.JSONObjectWithData(data, options: []) as? [String:AnyObject]
        } catch let error as NSError {
            print(error)
        }
    }
    return nil
}

然后你可以像这样读取数组：

if let dict = convertStringToDictionary(jsonText) {
    let array = dict["headings"] as? [String]
}

Answer 2

看起来你从json获取Dictionary并且每个键都包含Array ，你可以尝试这样的东西，首先声明一个Dictionary实例并将其与TableViewDataSource方法一起使用。

var response = [String: AnyObject]()

do {
     self.response = try NSJSONSerialization.JSONObjectWithData(data!, options: .MutableContainers) as! [String: AnyObject]
     print(dic)
}
catch let e as NSError {
     print(e.localizedDescription)
}

现在在tableView方法中

func numberOfSectionsInTableView(tableView: UITableView) -> Int {
    if let arr = self.response["headings"] as? [String] {
        return arr.count
    }
    return 0
}

func tableView(tableView: UITableView, titleForHeaderInSection section: Int) -> String? {
    let headings = self.response["headings"] as! [String]
    return headings[Int]
}

func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    if let arr = self.response["titles"] as? [[String]] {
        return arr[Int].count
    }
    return 0
}

func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
    let titles = self.response["titles"] as! [[String]]
    let details = self.response["details"] as! [[String]]       
    let cell = tableView.dequeueReusableCellWithIdentifier("cell") as! EmployeeCell
    cell.mainLabel?.text = titles[indexPath.section][indexPath.row]
    cell.detailLabel?.text = details[indexPath.section][indexPath.row]
    return cell
}

Answer 3

或者，您可以使用JSON解析库，如Argo或SwiftyJSON ，它们是为简化JSON解析而创建的。 它们都经过了良好的测试，可以为您处理边缘情况，例如JSON响应中缺少参数等。

使用Argo的一个例子：

假设JSON响应具有此格式（来自Twitter API ）

{
  "users": [
    {
      "id": 2960784075,
      "id_str": "2960784075",
      ...
    }
}

1-创建一个Swift类来表示响应

请注意， Response是一个包含User数组的类，这是另一个未在此处显示的类，但您明白了。

struct Response: Decodable {
    let users: [User]
    let next_cursor_str: String

    static func decode(j: JSON) -> Decoded<Response> {
        return curry(Response.init)
            <^> j <|| "users"
            <*> j <| "next_cursor_str"
    }
}

2-解析JSON

//Convert json String to foundation object
let json: AnyObject? = try? NSJSONSerialization.JSONObjectWithData(data, options: [])

//Check for nil    
if let j: AnyObject = json {
  //Map the foundation object to Response object
  let response: Response? = decode(j)
}

使用Swifty的示例

如官方文档中所述 ：

1-将JSON字符串转换为SwiftyJSON对象

if let dataFromString = jsonString.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false) {
    let json = JSON(data: dataFromString)
}

2-访问特定元素

如果数据是数组，则使用索引

//Getting a double from a JSON Array
let name = json[0].double

如果数据是字典，则使用密钥

//Getting a string from a JSON Dictionary
let name = json["name"].stringValue

2'-循环元素

排列

//If json is .Array
//The `index` is 0..<json.count's string value
for (index,subJson):(String, JSON) in json {
    //Do something you want
}

字典

//If json is .Dictionary
for (key,subJson):(String, JSON) in json {
   //Do something you want
}

Answer 4

我建议使用AlamofireObjectMapper。 该库允许您轻松地从json映射对象，如果与Alamofire结合使用，可以在服务器响应上转换和返回您的对象。 在您的情况下，对象映射本身应如下所示

class CustomResponseClass: Mappable {
    var headings: [String]?

    required init?(_ map: Map){

    }

    func mapping(map: Map) {
        headings <- map["headings"]
   }
}

这样就可以解析映射和解析json与tableViewController的逻辑。

AlamofireObjectMapper