iOS 联系人如何通过电话号码获取联系人

Question

我只想通过电话号码获取联系人的姓名和姓氏。 我试过了，但这太慢了，cpu 超过 %120。

let contactStore = CNContactStore()
            let keys = [CNContactGivenNameKey, CNContactFamilyNameKey, CNContactPhoneNumbersKey]
            var contacts = [CNContact]()
            do {
                try contactStore.enumerateContactsWithFetchRequest(CNContactFetchRequest.init(keysToFetch: keys), usingBlock: { (contact, cursor) in
                    if (!contact.phoneNumbers.isEmpty) {
                        for phoneNumber in contact.phoneNumbers {
                            if let phoneNumberStruct = phoneNumber.value as? CNPhoneNumber {
                                do {
                                    let libPhone = try util.parseWithPhoneCarrierRegion(phoneNumberStruct.stringValue)
                                    let phoneToCompare = try util.getNationalSignificantNumber(libPhone)
                                    if formattedPhone == phoneToCompare {
                                        contacts.append(contact)
                                    }
                                }catch {
                                    print(error)
                                }
                            }

                        }
                    }
                })
                if contacts.count > 0 {
                    contactName = (contacts.first?.givenName)! + " " + (contacts.first?.familyName)!
                    print(contactName)
                    completionHandler(contactName)
                }
            }catch {
                print(error)
            }

此外，当我使用电话号码工具包查找联系人时，其 cpu 增加并给出延迟响应。

var result: [CNContact] = []
        let nationalNumber = PhoneNumberKit().parseMultiple([phoneNumber])
        let number = nationalNumber.first?.toNational()
        print(number)

        for contact in self.addressContacts {
            if (!contact.phoneNumbers.isEmpty) {

                let phoneNumberToCompareAgainst = number!.componentsSeparatedByCharactersInSet(NSCharacterSet.decimalDigitCharacterSet().invertedSet).joinWithSeparator("")
                for phoneNumber in contact.phoneNumbers {
                    if let phoneNumberStruct = phoneNumber.value as? CNPhoneNumber {
                        let phoneNumberString = phoneNumberStruct.stringValue
                        let nationalContactNumber = PhoneNumberKit().parseMultiple([phoneNumberString])
                        let nationalContactNumberString = nationalContactNumber.first?.toNational()
                        if nationalContactNumberString == number {
                            result.append(contact)
                        }
                    }
                }
            }
        }

        return result

Answer 1

您实现的问题在于您在每次搜索时都访问地址簿。

相反，如果您在第一次访问后将地址簿内容保存在内存中，则不会达到如此高的 CPU 使用率。

1. 首先在您的控制器中保存一个惰性变量，它将保存地址簿内容：

    lazy var contacts: [CNContact] = { let contactStore = CNContactStore() let keysToFetch = [ CNContactFormatter.descriptorForRequiredKeysForStyle(.FullName), CNContactEmailAddressesKey, CNContactPhoneNumbersKey, CNContactImageDataAvailableKey, CNContactThumbnailImageDataKey] // Get all the containers var allContainers: [CNContainer] = [] do { allContainers = try contactStore.containersMatchingPredicate(nil) } catch { print("Error fetching containers") } var results: [CNContact] = [] // Iterate all containers and append their contacts to our results array for container in allContainers { let fetchPredicate = CNContact.predicateForContactsInContainerWithIdentifier(container.identifier) do { let containerResults = try contactStore.unifiedContactsMatchingPredicate(fetchPredicate, keysToFetch: keysToFetch) results.appendContentsOf(containerResults) } catch { print("Error fetching results for container") } } return results }()

   2. 当您查找具有特定电话号码的联系人时，遍历内存中的数组：

   .

    func searchForContactUsingPhoneNumber(phoneNumber: String) -> [CNContact] { var result: [CNContact] = [] for contact in self.contacts { if (!contact.phoneNumbers.isEmpty) { let phoneNumberToCompareAgainst = phoneNumber.componentsSeparatedByCharactersInSet(NSCharacterSet.decimalDigitCharacterSet().invertedSet).joinWithSeparator("") for phoneNumber in contact.phoneNumbers { if let phoneNumberStruct = phoneNumber.value as? CNPhoneNumber { let phoneNumberString = phoneNumberStruct.stringValue let phoneNumberToCompare = phoneNumberString.componentsSeparatedByCharactersInSet(NSCharacterSet.decimalDigitCharacterSet().invertedSet).joinWithSeparator("") if phoneNumberToCompare == phoneNumberToCompareAgainst { result.append(contact) } } } } } return result }

我用一个非常大的地址簿测试了它，它运行得很顺利。

这是拼凑在一起的整个视图控制器以供参考。

import UIKit
import Contacts

class ViewController: UIViewController {

    lazy var contacts: [CNContact] = {
        let contactStore = CNContactStore()
        let keysToFetch = [
                CNContactFormatter.descriptorForRequiredKeysForStyle(.FullName),
                CNContactEmailAddressesKey,
                CNContactPhoneNumbersKey,
                CNContactImageDataAvailableKey,
                CNContactThumbnailImageDataKey]

        // Get all the containers
        var allContainers: [CNContainer] = []
        do {
            allContainers = try contactStore.containersMatchingPredicate(nil)
        } catch {
            print("Error fetching containers")
        }

        var results: [CNContact] = []

        // Iterate all containers and append their contacts to our results array
        for container in allContainers {
            let fetchPredicate = CNContact.predicateForContactsInContainerWithIdentifier(container.identifier)

            do {
                let containerResults = try contactStore.unifiedContactsMatchingPredicate(fetchPredicate, keysToFetch: keysToFetch)
                results.appendContentsOf(containerResults)
            } catch {
                print("Error fetching results for container")
            }
        }

        return results
    }()

    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.

        let contact = searchForContactUsingPhoneNumber("(555)564-8583")
        print(contact)
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }

    func searchForContactUsingPhoneNumber(phoneNumber: String) -> [CNContact] {

        var result: [CNContact] = []

        for contact in self.contacts {
            if (!contact.phoneNumbers.isEmpty) {
                let phoneNumberToCompareAgainst = phoneNumber.componentsSeparatedByCharactersInSet(NSCharacterSet.decimalDigitCharacterSet().invertedSet).joinWithSeparator("")
                for phoneNumber in contact.phoneNumbers {
                    if let phoneNumberStruct = phoneNumber.value as? CNPhoneNumber {
                        let phoneNumberString = phoneNumberStruct.stringValue
                        let phoneNumberToCompare = phoneNumberString.componentsSeparatedByCharactersInSet(NSCharacterSet.decimalDigitCharacterSet().invertedSet).joinWithSeparator("")
                        if phoneNumberToCompare == phoneNumberToCompareAgainst {
                            result.append(contact)
                        }
                    }
                }
            }
        }

        return result
    }
}

我对懒惰的 var 部分使用了flohei 的答案。

Answer 2

SWIFT 4 更新

1) 添加到.plist

<key>NSContactsUsageDescription</key>
<string>Our application needs to your contacts</string>

2）如果您没有授权，请请求授权

func requestAccess() {

    let store = CNContactStore()
    store.requestAccess(for: .contacts) { granted, error in
        guard granted else {
            DispatchQueue.main.async {
               self.presentSettingsActionSheet()
            }
            return
        }
    }
}

func presentSettingsActionSheet() {
    let alert = UIAlertController(title: "Permission to Contacts", message: "This app needs access to contacts in order to ...", preferredStyle: .actionSheet)
    alert.addAction(UIAlertAction(title: "Go to Settings", style: .default) { _ in
        let url = URL(string: UIApplicationOpenSettingsURLString)!
        UIApplication.shared.open(url)
    })
    alert.addAction(UIAlertAction(title: "Cancel", style: .cancel))
    present(alert, animated: true)
}

2）如果您之前要求，请检查授权状态

    if CNContactStore.authorizationStatus(for: .contacts) == .authorized {
        getContacts()

    }

3) 呼叫获取联系人

    var contacts = [CNContact]()

    func getContacts(){

    let contactStore = CNContactStore()
    let keys = [CNContactGivenNameKey, CNContactFamilyNameKey, CNContactPhoneNumbersKey, CNContactImageDataAvailableKey, CNContactThumbnailImageDataKey]
    let request = CNContactFetchRequest(keysToFetch: keys as [CNKeyDescriptor])
    request.sortOrder = CNContactSortOrder.givenName

    do {
        try contactStore.enumerateContacts(with: request) {
            (contact, stop) in
            self.contacts.append(contact)
        }
    }
    catch {
        print("unable to fetch contacts")
    }
}

4)这是获取联系人姓名或号码的功能

    func getNameFromContacts(number: String) -> String {
    var contactFetched : CNContact
    var contactName = ""
    if contacts.count > 0 {

        let numberToBeCompared = number.components(separatedBy:CharacterSet.decimalDigits.inverted).joined(separator: "")
        for c in contacts {
            for n in c.phoneNumbers {
                if let numberRetrived = n.value as? CNPhoneNumber {
                     let numberRetrivedFixed = numberRetrived.stringValue.components(separatedBy:CharacterSet.decimalDigits.inverted).joined(separator: "")
                    if numberRetrivedFixed.elementsEqual(numberToBeCompared){
                        contactName = c.givenName
                        // OR get the contact --> c
                 contactFetched = c

                    }
                }
            }
        }

        return contactName

    } else {
        return ""
    }
}

Answer 3

必须为 Swift 5 进行这些更改：

lazy var contacts = {
            let contactStore = CNContactStore()
            let keysToFetch: [CNKeyDescriptor] = [
                CNContactFormatter.descriptorForRequiredKeys(for: .fullName),
                CNContactEmailAddressesKey as CNKeyDescriptor,
                CNContactPhoneNumbersKey as CNKeyDescriptor,
                CNContactImageDataAvailableKey as CNKeyDescriptor,
                CNContactThumbnailImageDataKey as CNKeyDescriptor]

            // Get all the containers
            var allContainers: [CNContainer] = []
            do {
                allContainers = try contactStore.containers(matching: nil)
            } catch {
                print("Error fetching containers")
            }

            var results: [CNContact] = []

            // Iterate all containers and append their contacts to our results array
            for container in allContainers {
                let fetchPredicate = CNContact.predicateForContactsInContainer(withIdentifier: container.identifier)

                do {
                    let containerResults = try     contactStore.unifiedContacts(matching: fetchPredicate, keysToFetch: keysToFetch)
                    results.append(contentsOf: containerResults)
                } catch {
                    print("Error fetching results for container")
                }
            }

            return results
        }()

对于迭代和发现：

    func searchForContactUsingPhoneNumber(phoneNumber: String) -> [CNContact] {
         var result: [CNContact] = []

         for contact in contacts {
             if (!contact.phoneNumbers.isEmpty) {
                let phoneNumberToCompareAgainst = phoneNumber.components(separatedBy: NSCharacterSet.decimalDigits.inverted).joined(separator: "")
                 for phoneNumber in contact.phoneNumbers {
                     if let phoneNumberStruct = phoneNumber.value as? CNPhoneNumber {
                         let phoneNumberString = phoneNumberStruct.stringValue
                        let phoneNumberToCompare = phoneNumberString.components(separatedBy: NSCharacterSet.decimalDigits.inverted).joined(separator: "")
                         if phoneNumberToCompare == phoneNumberToCompareAgainst {
                             result.append(contact)
                         }
                     }
                 }
              }
         }

         return result
    }