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[英]Is there a way to get the First day of the previous month and Last day of current month?
[英]MySQL: Select with first and last day of previous month
使用 PhpMyadmin,我有这句话工作:
SELECT id_order as Ref FROM t_orders WHERE DATE(invoice_date) = CURDATE()
现在我想提前为上个月的第一天重新放置“当前日期”(CURDATE)。
Ankit Bajpai 的回答解决了我的问题(谢谢):
SELECT id_order as Ref FROM t_orders WHERE DATE(invoice_date) >= concat(date_format(LAST_DAY(now() - interval 1 month),'%Y-%m-'),'01');
在 MYSQL 中,您可以尝试以下操作
上个月的第一天
select last_day(curdate() - interval 2 month) + interval 1 day
上个月的最后一天
select last_day(curdate() - interval 1 month)
当月的第一天
select last_day(curdate() - interval 1 month) + interval 1 day
当月的最后一天
select last_day(curdate())
对于 MS SQL 服务器:
DECLARE @firstDayOfLastMonth DATETIME = DATEADD(MONTH, -1, DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0))
DECLARE @lastDayOfLastMonth DATETIME = DATEADD(DAY, -1, DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0))
SELECT @firstDayOfLastMonth;
SELECT @lastDayOfLastMonth;
尝试以下查询:-
SELECT id_order as Ref
FROM t_orders
WHERE DATE(invoice_date) >= concat(date_format(LAST_DAY(now() - interval 1 month),'%Y-%m-'),'01');
仔细阅读后……您想要上个月的整个月。 你可以这样做:
SELECT id_order as Ref FROM t_orders
WHERE
DATE(invoice_date) >= DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE())-1, 0)
AND
DATE(invoice_date) <= DATEADD(month, DATEDIFF(MONTH, 0, GETDATE()), -1)
或
SELECT id_order as Ref FROM t_orders
WHERE
MONTH(DATE(invoice_date)) = MONTH(DATEADD(MONTH,-1,GETDATE()))
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