[英]Type 'x' does not conform to protocol 'UIPickerViewDataSource'
[英]Does not conform to protocol UIPickerViewDataSource
我不知道我的代码有什么问题。 我尝试按照本教程进行操作,但发生相同的错误。
错误:
类型“ FourthViewController”不符合协议“ UIPickerViewDataSource”
这是我的代码:
import UIKit
let characters = ["Jaja Bink", "Luke", "Han Solo", "Princess Leia"];
let weapons = ["LightSaber", "Pistol", "Keris"];
class FourthViewController: UIViewController, UIPickerViewDataSource, UIPickerViewDelegate {
@IBOutlet weak var doublePicker: UIPickerView!
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int {
return 2
}
func pickerView(pickerView: UIPickerView,
titleForRow row: Int,
forComponent component: Int) -> String? {
if component == 0 {
return characters[row]
} else {
return weapons[row]
}
}
func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int? {
if component == 0 {
return characters.count
} else {
return weapons.count
}
}
}
如果您使用的是Swift 3
,请替换协议UIPickerViewDataSource
的方法的不建议使用的版本。
不建议使用的协议方法
func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int {
return 1
}
Swift 3中的最新协议方法
func numberOfComponents(in pickerView: UIPickerView) -> Int {
return 1
}
注意:其他必需的协议方法也是如此。 即
不推荐使用:
func pickerView(pickerView: UIPickerView!, numberOfRowsInComponent component: Int) -> Int
最新版本:
func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int
因为您要求的委托方法不正确。
替换为:
func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
if component == 0 {
return characters.count
} else {
return weapons.count
}
}
您的委托方法返回Int?
这是不正确的。
您必须实现它的功能:
func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int
func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int
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