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PHP PDO MySQL根据另一个表的结果数组选择一个表的结果

[英]php PDO MySQL Select results of one table based on array of results from another table

以下查询将返回所有“阻止者”用户和所有“阻止”用户。 相当直接的查询。

$stmt=$db->prepare('SELECT blocker,blocked FROM list_blocked 
                    WHERE (blocked = :username AND blocker <> :username) 
                    OR (blocker = :username AND blocked <> :username)');
$stmt->bindParam(':username', $username);
$stmt->execute();

下一个查询将返回成员表中除当前$ username之外的所有用户名。

$query = $db->prepare("SELECT username FROM members WHERE username <> :username");
$query->bindValue(':user', $username;
$query->execute();
$row = $query->fetchAll();

我需要的是一种从第一个查询的结果中获取所有值的方法,不包括活动的$ username,然后从第二个查询中排除所有这些结果。

因此,例如:

Example results of first query:
jim blocked joe
larry blocked joe
steve blocked joe
joe blocked tony
jack blocked joe

Those results applied to the second query would look something like:
$query = $db->prepare("SELECT username FROM members WHERE username <> :username 
                       AND username <> jim 
                       AND username <> larry
                       AND username <> steve
                       AND username <> tony
                       AND username <> jack");

我究竟将如何实现这样的目标?

更新:

因此,我尝试使用子查询,但它不断返回“操作数应包含1列”

SELECT username FROM members WHERE username NOT IN (
    SELECT blocker,blocked FROM list_blocked 
                           WHERE (blocked = 'viraladmin' AND blocker <> 'viraladmin') 
                           OR (blocker = 'viraladmin' AND blocked <> 'viraladmin')
 ) 

另一个更新:

我尝试使用内部联接来实现此目的,但是结果总是返回空,我认为这是因为实际上没有任何联接。

SELECT members.username, list_blocked.blocker, list_blocked.blocked
FROM members
INNER JOIN list_blocked 
ON members.username = list_blocked.blocker
AND members.username = list_blocked.blocked
WHERE members.username <>  'username' 
AND (list_blocked.blocked = 'username' AND list_blocked.blocker <> 'username') 
OR (list_blocked.blocker = 'username' AND list_blocked.blocked <> 'username')

您可以使用子查询来完成此操作:

SELECT username FROM members WHERE username NOT IN (
SELECT blocker,blocked FROM list_blocked 
                WHERE (blocked = :username AND blocker <> :username) 
                OR (blocker = :username AND blocked <> :username)
 ) 

已编辑-为了适合SQL查询,您需要在子查询中进行合并,以便返回的结果不超过一栏。

SELECT username FROM members WHERE username NOT IN (
   SELECT blocker as username FROM list_blocked 
                WHERE (blocked = :username AND blocker <> :username) 
                OR (blocker = :username AND blocked <> :username)
   UNION
   SELECT blocked as username FROM list_blocked 
                WHERE (blocked = :username AND blocker <> :username) 
                OR (blocker = :username AND blocked <> :username)
 ) 

您也可以为此使用LEFT JOIN - NULL模式。

SELECT username
FROM members AS m
LEFT JOIN list_blocked AS b
ON m.username IN (b.blocker, b.blocked)
    AND ((blocked = :username AND blocker <> :username) 
        OR (blocker = :username AND blocked <> :username))
WHERE b.blocked IS NULL

仅当值不存在时,才基于返回行中的模式

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