PHP PDO MySQL根據另一個表的結果數組選擇一個表的結果

Question

以下查詢將返回所有“阻止者”用戶和所有“阻止”用戶。 相當直接的查詢。

$stmt=$db->prepare('SELECT blocker,blocked FROM list_blocked 
                    WHERE (blocked = :username AND blocker <> :username) 
                    OR (blocker = :username AND blocked <> :username)');
$stmt->bindParam(':username', $username);
$stmt->execute();

下一個查詢將返回成員表中除當前$ username之外的所有用戶名。

$query = $db->prepare("SELECT username FROM members WHERE username <> :username");
$query->bindValue(':user', $username;
$query->execute();
$row = $query->fetchAll();

我需要的是一種從第一個查詢的結果中獲取所有值的方法，不包括活動的$ username，然后從第二個查詢中排除所有這些結果。

因此，例如：

Example results of first query:
jim blocked joe
larry blocked joe
steve blocked joe
joe blocked tony
jack blocked joe

Those results applied to the second query would look something like:
$query = $db->prepare("SELECT username FROM members WHERE username <> :username 
                       AND username <> jim 
                       AND username <> larry
                       AND username <> steve
                       AND username <> tony
                       AND username <> jack");

我究竟將如何實現這樣的目標？

更新：

因此，我嘗試使用子查詢，但它不斷返回“操作數應包含1列”

SELECT username FROM members WHERE username NOT IN (
    SELECT blocker,blocked FROM list_blocked 
                           WHERE (blocked = 'viraladmin' AND blocker <> 'viraladmin') 
                           OR (blocker = 'viraladmin' AND blocked <> 'viraladmin')
 ) 

另一個更新：

我嘗試使用內部聯接來實現此目的，但是結果總是返回空，我認為這是因為實際上沒有任何聯接。

SELECT members.username, list_blocked.blocker, list_blocked.blocked
FROM members
INNER JOIN list_blocked 
ON members.username = list_blocked.blocker
AND members.username = list_blocked.blocked
WHERE members.username <>  'username' 
AND (list_blocked.blocked = 'username' AND list_blocked.blocker <> 'username') 
OR (list_blocked.blocker = 'username' AND list_blocked.blocked <> 'username')

Answer 1

您可以使用子查詢來完成此操作：

SELECT username FROM members WHERE username NOT IN (
SELECT blocker,blocked FROM list_blocked 
                WHERE (blocked = :username AND blocker <> :username) 
                OR (blocker = :username AND blocked <> :username)
 ) 

已編輯-為了適合SQL查詢，您需要在子查詢中進行合並，以便返回的結果不超過一欄。 ：

SELECT username FROM members WHERE username NOT IN (
   SELECT blocker as username FROM list_blocked 
                WHERE (blocked = :username AND blocker <> :username) 
                OR (blocker = :username AND blocked <> :username)
   UNION
   SELECT blocked as username FROM list_blocked 
                WHERE (blocked = :username AND blocker <> :username) 
                OR (blocker = :username AND blocked <> :username)
 ) 

Answer 2

您也可以為此使用LEFT JOIN - NULL模式。

SELECT username
FROM members AS m
LEFT JOIN list_blocked AS b
ON m.username IN (b.blocker, b.blocked)
    AND ((blocked = :username AND blocker <> :username) 
        OR (blocker = :username AND blocked <> :username))
WHERE b.blocked IS NULL

僅當值不存在時，才基於返回行中的模式