[英]What is the best way to translate this recursive python method into Java?
[英]how can I best translate this java method to python
我怎么能写更少的python2代码来实现同样的事情,需要加密结果是一样的。
b[i++] = (byte) 172;
以什么方式将int转换为python2中的byte ...
public static String encryptPassword(String content) {
String resultString = "";
String appkey = "ftjf,ckdfkl";
byte[] a = appkey.getBytes();
byte[] datSource = content.getBytes();
byte[] b = new byte[a.length + 4 + datSource.length];
int i;
for (i = 0; i < datSource.length; i++) {
b[i] = datSource[i];
}
b[i++] = (byte) 172;
b[i++] = (byte) 163;
b[i++] = (byte) 161;
b[i++] = (byte) 163;
for (int k = 0; k < a.length; k++) {
b[i] = a[k];
i++;
}
try {
MessageDigest md5 = MessageDigest.getInstance("MD5");
md5.update(b);
resultString = new HexBinaryAdapter().marshal(md5.digest());
} catch (Exception e) {
}
return resultString.toLowerCase();
}
public static void main(String[] args) {
System.out.print(encryptPassword("123456"));
}
使用chr
在python中获取一个字节的char。
from Crypto.Hash import MD5
key = 'ftjf,ckdfkl'
src= '123'
b = src+chr(172)+chr(163)+chr(161)+chr(163)+key
md5 = MD5.new()
md5.update(b)
text = md5.hexdigest()
print text
给定src'123',输出为:
eedb36cc3204923459dcf891224a0c1d
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