[英]How do I limit my users input to a single digit? (Python)
我想让我的程序说出“无效输入”(如果输入的是2位或更多位数字),那么有什么方法可以将我的用户输入限制为python中的一位数字?
这是我的代码:
print('List Maker')
tryagain = ""
while 'no' not in tryagain:
list = []
for x in range(0,10):
number = int(input("Enter a number: "))
list.append(number)
print('The sum of the list is ',sum(list))
print('The product of the list is ',sum(list) / float(len(list)))
print('The minimum value of the list is ',min(list))
print('The maximum vlaue of the list is ',max(list))
print(' ')
tryagain = input('Would you like to restart? ').lower()
if 'no' in tryagain:
break
print('Goodbye')
使用while
循环而不是for
循环,当您有10位数字时中断,并拒绝接受9以上的任何数字:
numbers = []
while len(numbers) < 10:
number = int(input("Enter a number: "))
if not 1 <= number <= 9:
print('Only numbers between 1 and 9 are accepted, try again')
else:
numbers.append(number)
请注意,我将列表重命名为numbers
; list
是内置类型,您通常希望避免使用内置名称。
根据先前的答案 ,还有一种选择只获取一个字符:
import termios
import sys, tty
def getch():
fd = sys.stdin.fileno()
old_settings = termios.tcgetattr(fd)
try:
tty.setraw(fd)
ch = sys.stdin.read(1)
finally:
termios.tcsetattr(fd, termios.TCSADRAIN, old_settings)
return ch
numbers = []
while len(numbers) < 10:
try:
ch = int(getch())
except:
print 'error...'
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