[英]Javascript changes reset when page reloads
我的网站有一页结帐,所以我决定将其分为5部分,并使用javascript一次显示一两个。
参见下面的代码:
<fieldset id="vm-fieldset-pricelist" class="vm-fieldset-pricelist"> ... </fieldset>
<div id="coupon-section" class="coupon-section display-none"> ... </div>
<fieldset id="shipment-section" class="shipment-section display-none"> ... </fieldset>
<div id="edit-account-section" class="billto-shipto display-none"> ... </div>
<div id="part-five" class="display-none"> ... </div>
<?php
$user = JFactory::getUser();
if ($user->guest) {
$usercheckin = '_notloggedin';
} else {
$usercheckin = '_loggedin';
}
?>
<button type="button" id="one-to-two<?php echo $usercheckin ?>" class="sabz-button pull-right" onclick="cartButtonHandler(this.id); return false;"><?php echo vmText::_('COM_VIRTUEMART_CHECKOUT_TITLE')?> </button>
<script>
window.cartButtonHandler = function(button_id) {
switch(button_id) {
case 'one-to-two_notloggedin':
document.getElementById("vm-fieldset-pricelist").className = "display-none";
document.getElementById("com-form-login").className = "";
document.getElementById(button_id).innerHTML = "ثبت اطلاعات و ادامه خرید";
document.getElementById(button_id).className = "abi-button pull-right";
document.getElementById(button_id).id = 'two-to-three';
break;
case 'one-to-two_loggedin':
document.getElementById("vm-fieldset-pricelist").className = "display-none";
document.getElementById("edit-account-section").className = "billto-shipto display-none";
document.getElementById("shipment-section").className = "shipment-section";
document.getElementById(button_id).innerHTML = "ثبت اطلاعات و ادامه خرید";
document.getElementById(button_id).className = "abi-button pull-right";
document.getElementById(button_id).id = 'two-to-three';
break;
case 'two-to-three':
document.getElementById("edit-account-section").className = "display-none";
document.getElementById("shipment-section").className = "display-none";
document.getElementById("coupon-section").className = "coupon-section";
document.getElementById(button_id).innerHTML = "بازبینی و تایید سفارش";
document.getElementById(button_id).id = 'three-to-four';
break;
case 'three-to-four':
document.getElementById("part-chahar").className = "";
document.getElementById("vm-fieldset-pricelist").className = "vm-fieldset-pricelist";
document.getElementById("edit-account-section").className = "billto-shipto display-none";
document.getElementById("shipment-section").className = "shipment-section";
document.getElementById("coupon-section").className = "coupon-section";
document.getElementById("handlerbutton-section").className = "display-none";
document.getElementById(button_id).id = 'four-to-five';
break;
case 'four-to-five':
alert(button_id);
break;
}
}
</script>
首先,我不了解javascript,是否有更好的方法在javascript或jquery或...中做到这一点?
我的问题:例如,“优惠券部分”中的用户输入优惠券代码并单击“提交”按钮时,请注意,优惠券提交按钮与“下一步”按钮不同,页面会重新加载,并弹出第一步。 或当用户选中复选框或任何其他交互时,页面会重新加载,并弹出第一步。
我如何保存javascript更改并使它们重新加载到页面上,以便用户与表单进行交互后可以停留在同一步骤上? 我想可以使用Cookie或其他方法解决此问题,但我不知道该怎么做。
1.通过Jquery轻松进行html(DOM)操纵和选择。
浏览文档SessionStorage,(在重新加载时在broswer会话中设置和获取项目)
学习Json,创建一个json结构来记录进度,并创建一个函数基于该json加载该部分。(使所有内容均由数据驱动),例如:
[
{sectionName:“ section1”,进度:“ started”},{sectionName:“ section2”,进度:“ incomplete”},
]
希望这可以帮助
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