[英]MySQL SUM With Grouped Date
如何获取带有分组日期的数据价格?
SELECT store.date, store.pic, owner.name,
SUM (CASE WHEN [>>GROUPED store.date<<] THEN store.price) AS total_price
FROM store
JOIN owner
ON store.pic = owner.name GROUP BY store.date
我想这样显示:
+-------------+------+------------+
| date | name | price |
+-------------+------+------------+
| 2016-09-30 | John | 100000.00 |
| 2016-09-29 | Rey | 125000.00 |
+-------------+------+------------+
试试这个可能对您有帮助,
SELECT store.date, store.pic, owner.name,SUM(store.price) AS total_price
FROM store
JOIN OWNER ON store.pic = owner.name
GROUP BY store.date
我不明白为什么您在查询中使用了case语句
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