[英]SQL Server : compare row values in a group and update a field in the same table
[英]SQL Server - Compare values from the same table
在SQL Server中,我有一个包含以下数据(tblUserSettings)的表:
| CountryID | CityID | UserType | Value1 | Value2 | Value3 |
| 9 | 3 | 1 | 5 | 5 | 5 |
| 9 | 3 | 2 | NULL | NULL | NULL |
| 9 | 3 | 3 | 5 | 5 | 5 |
| 9 | 3 | 4 | 5 | 5 | 5 |
| 9 | 20 | 1 | 5 | 5 | 5 |
| 9 | 20 | 2 | NULL | NULL | NULL |
| 9 | 20 | 3 | 5 | 5 | 5 |
| 9 | 20 | 4 | 0 | 0 | 0 |
我需要将CityID = 20的所有UserTypes的所有值与CityID = 3的对应UserTypes的所有值进行比较。CountryID =9。要比较的列是:Value1,Value2,Value3。
我只需要知道它们是否彼此匹配即可。 我尝试执行以下操作:
SELECT CASE WHEN ISNULL(t1.Value1, 0) = ISNULL(t2.Value1, 0) THEN 1 ELSE 0 END AS Match1,
CASE WHEN ISNULL(t1.Value2, 0) = ISNULL(t2.Value2, 0) THEN 1 ELSE 0 END AS Match2,
CASE WHEN ISNULL(t1.Value3, 0) = ISNULL(t2.Value3, 0) THEN 1 ELSE 0 END AS Match3
FROM tblUserSettings t1
INNER JOIN tblUserSettings t2 ON t1.CountryID = t2.CountryID
AND t1.UserType = t2.UserType
AND t1.CityID = 3
AND t2.CityID = 20
WHERE t1.CountryID = 9
它给了我以下结果,我必须进一步处理以定义是否所有内容都匹配。
| Match1 | Match2 | Match3 |
| 1 | 1 | 1 |
| 1 | 1 | 1 |
| 1 | 1 | 1 |
| 0 | 0 | 0 |
我能以某种方式使输出中只有一列和一行吗?-对于所有匹配项,只接收1;如果至少一个不匹配,则只接收0?
如果您希望在所有值都匹配时只获得包含1
一列,如果不匹配则返回0
,请使用,
SELECT
CASE WHEN ISNULL(t1.Value1, 0) = ISNULL(t2.Value1, 0)
AND ISNULL(t1.Value2, 0) = ISNULL(t2.Value2, 0)
AND ISNULL(t1.Value3, 0) = ISNULL(t2.Value3, 0)
THEN 1 ELSE 0 END AS Match
FROM tblUserSettings t1
INNER JOIN tblUserSettings t2 ON t1.CountryID = t2.CountryID
AND t1.UserType = t2.UserType
AND t1.CityID = 3
AND t2.CityID = 20
WHERE t1.CountryID = 9
如果您想比较所有城市而不只是两个城市,则应该能够通过分组而不是加入来进行比较。
就像是:
SELECT
CASE WHEN
max(Value1)-min(Value1) = 0
AND max(Value2)-min(Value2) = 0
AND max(Value3)-min(Value3) = 0
THEN 1 ELSE 0 AS Match
FROM tblUserSettings
GROUP BY CountryID,UserType
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