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[英]SQL Server : compare row values in a group and update a field in the same table
[英]SQL Server - Compare values from the same table
在SQL Server中,我有一個包含以下數據(tblUserSettings)的表:
| CountryID | CityID | UserType | Value1 | Value2 | Value3 |
| 9 | 3 | 1 | 5 | 5 | 5 |
| 9 | 3 | 2 | NULL | NULL | NULL |
| 9 | 3 | 3 | 5 | 5 | 5 |
| 9 | 3 | 4 | 5 | 5 | 5 |
| 9 | 20 | 1 | 5 | 5 | 5 |
| 9 | 20 | 2 | NULL | NULL | NULL |
| 9 | 20 | 3 | 5 | 5 | 5 |
| 9 | 20 | 4 | 0 | 0 | 0 |
我需要將CityID = 20的所有UserTypes的所有值與CityID = 3的對應UserTypes的所有值進行比較。CountryID =9。要比較的列是:Value1,Value2,Value3。
我只需要知道它們是否彼此匹配即可。 我嘗試執行以下操作:
SELECT CASE WHEN ISNULL(t1.Value1, 0) = ISNULL(t2.Value1, 0) THEN 1 ELSE 0 END AS Match1,
CASE WHEN ISNULL(t1.Value2, 0) = ISNULL(t2.Value2, 0) THEN 1 ELSE 0 END AS Match2,
CASE WHEN ISNULL(t1.Value3, 0) = ISNULL(t2.Value3, 0) THEN 1 ELSE 0 END AS Match3
FROM tblUserSettings t1
INNER JOIN tblUserSettings t2 ON t1.CountryID = t2.CountryID
AND t1.UserType = t2.UserType
AND t1.CityID = 3
AND t2.CityID = 20
WHERE t1.CountryID = 9
它給了我以下結果,我必須進一步處理以定義是否所有內容都匹配。
| Match1 | Match2 | Match3 |
| 1 | 1 | 1 |
| 1 | 1 | 1 |
| 1 | 1 | 1 |
| 0 | 0 | 0 |
我能以某種方式使輸出中只有一列和一行嗎?-對於所有匹配項,只接收1;如果至少一個不匹配,則只接收0?
如果您希望在所有值都匹配時只獲得包含1
一列,如果不匹配則返回0
,請使用,
SELECT
CASE WHEN ISNULL(t1.Value1, 0) = ISNULL(t2.Value1, 0)
AND ISNULL(t1.Value2, 0) = ISNULL(t2.Value2, 0)
AND ISNULL(t1.Value3, 0) = ISNULL(t2.Value3, 0)
THEN 1 ELSE 0 END AS Match
FROM tblUserSettings t1
INNER JOIN tblUserSettings t2 ON t1.CountryID = t2.CountryID
AND t1.UserType = t2.UserType
AND t1.CityID = 3
AND t2.CityID = 20
WHERE t1.CountryID = 9
如果您想比較所有城市而不只是兩個城市,則應該能夠通過分組而不是加入來進行比較。
就像是:
SELECT
CASE WHEN
max(Value1)-min(Value1) = 0
AND max(Value2)-min(Value2) = 0
AND max(Value3)-min(Value3) = 0
THEN 1 ELSE 0 AS Match
FROM tblUserSettings
GROUP BY CountryID,UserType
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