根据逗号数分割字符串

Question

我有一个用逗号分隔的文本。

例如：

FOO( something, BOO(tmp, temp), something else)

可能其他内容也包含带逗号的字符串...

我想将FOO框内的文本拆分为元素，然后粘贴元素。

我所知道的是FOO必须有两个逗号。

我该如何将FOO的内容分为三个要素？

备注： 其他可能是BOO（ddd，ddd）或简单地ddd 。 我不能假设'FOO \\（\\ w +，BOO（\\ w +，\\ w +），\\ w + \\）'的简单正则表达式

Answer 1

假设该字符串是Python代码，则可以为此使用解析器 。 如果仔细查看结果，您可能会同意它的效果不如最初看起来的那么糟糕。

>>> from parser import *
>>> source="FOO( something, BOO(tmp, temp), something)"
>>> st=suite(source)
>>> st2tuple(st)
(257, (268, (269, (270, (271, (272, (302, (306, (307, (308, (309, (312, (313, (314, (315, (316, (317, (318, (319, (320, (1, 'FOO')), (322, (7, '('), (330, (331, (302, (306, (307, (308, (309, (312, (313, (314, (315, (316, (317, (318, (319, (320, (1, 'something')))))))))))))))), (12, ','), (331, (302, (306, (307, (308, (309, (312, (313, (314, (315, (316, (317, (318, (319, (320, (1, 'BOO')), (322, (7, '('), (330, (331, (302, (306, (307, (308, (309, (312, (313, (314, (315, (316, (317, (318, (319, (320, (1, 'tmp')))))))))))))))), (12, ','), (331, (302, (306, (307, (308, (309, (312, (313, (314, (315, (316, (317, (318, (319, (320, (1, 'temp'))))))))))))))))), (8, ')')))))))))))))))), (12, ','), (331, (302, (306, (307, (308, (309, (312, (313, (314, (315, (316, (317, (318, (319, (320, (1, 'something'))))))))))))))))), (8, ')')))))))))))))))))), (4, ''))), (4, ''), (0, ''))

Answer 2

您可以使用此正则表达式

,(?=(?:(?:\([^)]*\))?[^)]*)+\)$)

在昏迷中分割您的字符串，机器人不在BOO（...）内部

样品

Answer 3

您可以使用支持递归的regex模块来完成此操作（用于处理嵌套结构）：

import regex

s = 'FOO( something, BOO(tmp, temp), something else)'

pat = regex.compile(r'''(?(DEFINE) # inside a definition group
    # you can define subpatterns to use later
    (?P<elt>     # define the subpattern "elt"
        [^,()]*+
        (?:
            \( (?&elt) (?: , (?&elt) )* \)
            [^,()]*
        )*+
    )
)
# start of the main pattern
FOO\( \s*
    (?P<elt1> (?&elt) )  # capture group "elt1" contains the subpattern "elt"
    , \s*
    (?P<elt2> (?&elt) )  # same here
    , \s*
    (?P<elt3> (?&elt) )  # etc.
\)''', regex.VERSION1 | regex.VERBOSE )

m = pat.search(s)

print(m.group('elt1'))
print(m.group('elt2'))
print(m.group('elt3'))

演示

Answer 4

假设您需要FOO中的元素列表，因此请先对其进行预处理

>>> s = 'FOO( something, BOO(tmp, temp), something else)'
>>> s
'FOO( something, BOO(tmp, temp), something else)'
>>> s = re.sub(r'^[^(]+\(|\)\s*$','',s)
>>> s
' something, BOO(tmp, temp), something else'

使用正则表达式模块：

>>> regex.split(r'[^,(]+\([^)]+\)(*SKIP)(?!)|,', s)
[' something', ' BOO(tmp, temp)', ' something else']

• [^,(]+\\([^)]+\\)(*SKIP)(?!)跳过模式[^,(]+\\([^)]+\\)
• |,实际上是分割输入字符串的替代模式，在这种情况下,

另一个例子：

>>> t = 'd(s,sad,e),g(3,2),c(d)'
>>> regex.split(r'[^,(]+\([^)]+\)(*SKIP)(?!)|,', t)
['d(s,sad,e)', 'g(3,2)', 'c(d)']