[英]Sending variables from one method to another
因此,我有一个程序可以计算平均成绩,最高成绩,最低成绩以及没有最低成绩的平均值。 因此,对于确定没有最低成绩的新平均值的方法,我想使用在该方法中已经找到的最低成绩。
/**
* lowestGrade() - method will return lowest grade
* @return lowGrade
*/
public static double lowestGrade(double[] grades) {
double lowGrade = 100.0;
// for loop that goes through grades array and stores
// first grade found as highest grade
for (int i = 0; i < grades.length; i++) {
// if statement will determine true lowest grade
if ( grades[i] < lowGrade ) {
lowGrade = grades[i];
}
}
// Output
return lowGrade;
}
/**
* averageWOLowGrade() - method will calculate average without lowest grade
* @return newAverage
*/
public static void averageWOLowGrade(double[] grades) {
double newAverage = 0;
}
如前所述之前 ,你可以存储在字段中的最低等级:
private static double min = 0.0;
public static double lowestGrade(double[] grades) {
// Set min and return its value.
return min = DoubleStream.of(grades).min().getAsDouble();
}
public static double averageWOLowGrade(double[] grades) {
return DoubleStream.of(grades).filter(x -> x != min)
.average()
.getAsDouble();
}
请记住,执行顺序在这里很重要。 我宁愿计算值两次,而不是在静态变量中管理状态。 甚至更好:一次计算所有结果:
public static Stats computeStats(double[] grades) {
double min, max;
min = max = grades[0];
double sum = 0.0;
for (double grade : grades) {
if (grade < min) {
min = grade;
} else if (grade > max) {
max = grade;
}
sum += grade;
}
double avg = sum / grades.length;
int len = 0;
sum = 0.0;
for (double grade : grades) {
if (grade != min) {
sum += grade;
len++;
}
}
return new Stats(min, max, avg, sum / len);
}
static class Stats {
public final double min;
public final double max;
public final double avg;
public final double avgWithoutMin;
Stats(double min, double max, double avg, double avgWithoutMin) {
this.min = min;
this.max = max;
this.avg = avg;
this.avgWithoutMin = avgWithoutMin;
}
}
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