簡體   English   中英

將變量從一種方法發送到另一種方法

[英]Sending variables from one method to another

因此,我有一個程序可以計算平均成績,最高成績,最低成績以及沒有最低成績的平均值。 因此,對於確定沒有最低成績的新平均值的方法,我想使用在該方法中已經找到的最低成績。

/**
 * lowestGrade() - method will return lowest grade
 * @return lowGrade
 */
public static double lowestGrade(double[] grades) {

    double lowGrade = 100.0;

    // for loop that goes through grades array and stores
    // first grade found as highest grade
    for (int i = 0; i < grades.length; i++) {

        // if statement will determine true lowest grade
        if ( grades[i] < lowGrade ) {
            lowGrade = grades[i];
        }
    }

    // Output
    return lowGrade;
}

/**
 * averageWOLowGrade() - method will calculate average without lowest grade
 * @return newAverage
 */
public static void averageWOLowGrade(double[] grades) {
    double newAverage = 0;  
}

如前所述之前 ,你可以存儲在字段中的最低等級:

private static double min = 0.0;

public static double lowestGrade(double[] grades) {
    // Set min and return its value.
    return min = DoubleStream.of(grades).min().getAsDouble();
}

public static double averageWOLowGrade(double[] grades) {
    return DoubleStream.of(grades).filter(x -> x != min)
                                  .average()
                                  .getAsDouble();
}

請記住,執行順序在這里很重要。 我寧願計算值兩次,而不是在靜態變量中管理狀態。 甚至更好:一次計算所有結果:

public static Stats computeStats(double[] grades) {
    double min, max;
    min = max = grades[0];
    double sum = 0.0;

    for (double grade : grades) {
        if (grade < min) {
            min = grade;
        } else if (grade > max) {
            max = grade;
        }
        sum += grade;
    }

    double avg = sum / grades.length;
    int len = 0;
    sum = 0.0;

    for (double grade : grades) {
        if (grade != min) {
            sum += grade;
            len++;
        }
    }

    return new Stats(min, max, avg, sum / len);
}

static class Stats {
    public final double min;
    public final double max;
    public final double avg;
    public final double avgWithoutMin;

    Stats(double min, double max, double avg, double avgWithoutMin) {
        this.min = min;
        this.max = max;
        this.avg = avg;
        this.avgWithoutMin = avgWithoutMin;
    }
}

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM