Bash：使用for循环读取填充数组

Question

在我的一个课程中，我被分配了一个问题集。 在其中一个练习中，我必须使用for循环和read命令接受三个字符串，然后在我的数组中使用（...）中的select选项。 下面是我的代码，但我似乎无法使用for循环正确填充数组。 我已经找到了一些替代方案，但我必须使用这种通用结构。

echo Please type in 3 foods you like:
for xx in `seq 1 3`; do
    read -p "enter food $xx " array[$xx]
    echo $array
done

PS3='Now Select the food you like the best: '
select option in array
do
    echo "The option you have selected is: $option"
    break
done

Answer 1

阵列填充正确; 你只是没有正确扩展它。

# Don't use seq; just use bash's C-style for loop.
# The only reason to avoid this kind of loop is
# to make your shell script POSIX-compatible, but
# seq isn't part of the POSIX standard either.
  for ((xx=1; xx<=3; xx++)); do   # Don't use seq
    read -p "Enter foo $xx" array[xx]
    echo "${array[@]}"
done

PS3='Now Select the food you like the best: '
select option in "${array[@]}"
do
    echo "The option you have selected is: $option"
    break
done