在android中调用soap webservices

Question

我是在android中调用肥皂网络服务的新手，我称为Url，我也发送了参数，

我收到一个错误，错误是： 服务器无法处理请求。 --->对象引用未设置为对象的实例。 faultactor：“ null”详细信息：org.kxml2.kdom.Node

肥皂的描述链接如下： selticketprice

调用soap webservices的Java代码是：

                   protected String doInBackground(String... params) {
    // TODO Auto-generated method stub
    final SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME_memberRegistration);
        // SerializationUtils.serialize(bFile);
        request.addProperty("fareMediaType", "SJT");
        request.addProperty("fromValue", "1");
        request.addProperty("toValue", "3");
        request.addProperty("ticketDate", "2016-09-29");
        request.addProperty("lang", "en");
        final SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
                SoapEnvelope.VER11);
        envelope.headerIn = new Element[1];
        envelope.headerIn[0] = buildAuthHeader();
        new MarshalBase64().register(envelope);

        envelope.setOutputSoapObject(request);

        envelope.dotNet = true;
        HttpTransportSE androidHttpTransport = new HttpTransportSE(signUpURL);
        try {
            androidHttpTransport.call(SOAP_ACTION_memberRegistration, envelope);
            SoapPrimitive response = (SoapPrimitive) envelope.getResponse();
            res = response.toString();

        } catch (Exception e) {
            Log.e("exception", e.getMessage(),e);
        }

    return res;
}

private Element buildAuthHeader() {
    Element h = new Element().createElement(NAMESPACE, "AuthHeader");
    Element username = new Element().createElement(NAMESPACE, "Username");
    username.addChild(Node.TEXT, "name");
    h.addChild(Node.ELEMENT, username);
    Element pass = new Element().createElement(NAMESPACE, "Password");
    pass.addChild(Node.TEXT, "*******");
    h.addChild(Node.ELEMENT, pass);

    return h;
}     

Answer 1

您是否考虑过不使用Soap库来发出Soap请求？ 这更加准确，您可以跟踪发生异常的地方（与库相反）。 对于服务更改且您无法使用该库的长期情况，这也是最佳选择。 在这里通过我的回答在android中调用Soap Web服务