[英]deleting the head node in a linked list
如何修复delete方法,使其也可以删除头节点?
class LinkedListNode():
def __init__(self, data=None, next_node=None):
self.data = data
self.next_node = next_node
def data(self):
return self.data
def next_node(self):
return self.next_node
def set_next_node(self, next_node):
self.next_node = next_node
def search(self, data):
index = 0
while self.next_node != None and self != None:
if self.data == data:
return index
else:
self = self.next_node
index += 1
return -1
def delete(self, data):
head = self
if self.data == data:
head = self.next_node
while self.next_node != None and self != None:
if self.next_node.data == data:
if self.next_node.next_node != None:
self.next_node = self.next_node.next_node
else:
self.next_node = None
else:
self = self.next_node
return head
def print(self):
while self.next_node != None:
print("%s: %s" % ("current node data is", self.data))
self = self.next_node
if self.next_node == None and self != None:
print("%s: %s" % ("current node data is", self.data))
在测试文件中,我有:
from LinkedListNode import *
head = LinkedListNode(3)
node1 = LinkedListNode('cat')
node2 = LinkedListNode('dog')
node3 = LinkedListNode(4)
head.set_next_node(node1)
node1.set_next_node(node2)
node2.set_next_node(node3)
print(head.search('dog'))
head.delete(3)
head.delete(4)
head.print()
我得到:
2
current node data is: 3
current node data is: cat
current node data is: dog
Process finished with exit code 0
首先,我相信您不应该在搜索方法中重新分配“自我”:
def search(self, data):
index = 0
while self.next_node != None and self != None:
if self.data == data:
return index
else:
self = self.next_node
index += 1
return -1
将其替换为简单的递归版本,然后重试:
def search(self, data):
if self.data == data:
return 0
elif self.next_node == None:
return -1
else:
idx = self.next_node.search(data)
if idx == -1:
return -1
else:
return 1 + idx
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