删除由tkinter中的函数创建的标签

Question

我有一个生成标签并使用.place（）将其放到窗口上的函数。 虽然稍后在我的程序中我希望删除这些标签。 我将如何使用.place_forget（）隐藏所有标签？ 正如我试图调用.place_forget（）一样，只删除了其中一个标签。 并且有几种这样的标签。

这是产生标签的函数：

def playerTab(team, name, pos, pts, reb, ast, stl, blk, to, y):
    global playerTeam, playerName, playerPosition, playerPoints, playerRebounds, playerAssists, playerSteals, playerBlocks, playerTurnovers
    #Print the team
    playerTeam = Label(statWindow, bg = "white", text = team)
    playerTeam.config(height = 1, width = 13)
    playerTeam.place(x=20,y=y)
    #Print the name
    playerName = Label(statWindow, bg = "white", text = name)
    playerName.config(height = 1, width = 25)
    playerName.place(x=119,y=y)
    #Print the players position
    playerPosition = Label(statWindow, bg = "white", text = pos)
    playerPosition.config(height = 1, width = 4)
    playerPosition.place(x=302,y=y)
    #Print the players average points
    playerPoints = Label(statWindow, bg = "white", text = pts)
    playerPoints.config(height = 1, width = 4)
    playerPoints.place(x=338,y=y)
    #Print the players average rebounds
    playerrebounds = Label(statWindow, bg = "white", text = reb)
    playerrebounds.config(height = 1, width = 4)
    playerrebounds.place(x=374,y=y)
    playerAssists = Label(statWindow, bg = "white", text = ast)
    playerAssists.config(height = 1, width = 4)
    playerAssists.place(x=410,y=y)
    playerSteals = Label(statWindow, bg = "white", text = stl)
    playerSteals.config(height = 1, width = 4)
    playerSteals.place(x=446,y=y)
    playerBlocks = Label(statWindow, bg = "white", text = blk)
    playerBlocks.config(height = 1, width = 4)
    playerBlocks.place(x=482,y=y)
    playerTurnovers = Label(statWindow, bg = "white", text = to)
    playerTurnovers.config(height = 1, width = 4)
    playerTurnovers.place(x=518,y=y)

该代码是非常重复的，但是在现阶段对我来说这不是问题。 尽管我也欢迎提高效率的方法。 然后，此函数使用前一个产生许多标签：

def sortByPoints():
    foundPlayers = []
    with open ('PlayerList.csv') as csvfile:
        reader = csv.DictReader(csvfile)
        for row in reader:
            foundPlayers.append((int(row['Average PTS']), int(row['PlayerCode'])))
    sortedPlayers = sorted(foundPlayers, reverse=True)
    print(sortedPlayers)
    for i in range(len(sortedPlayers)):
        with open ('PlayerList.csv') as csvfile:
            reader = csv.DictReader(csvfile)
            for row in reader:
                if row['PlayerCode'] == str(sortedPlayers[i][1]):
                    print(sortedPlayers[i][1])
                    playerTab(row['Team'], (row['First Name'] + row['Last Name']), row['Position'], row['Average PTS'], row['Average REB'], row['Average AST'], row['Average STL'], row['Average BLK'], row['Average TO'], (120 + (i * 25)))

然后，我将如何隐藏所有产生的标签。 还是不可能与我所采用的方法有关？ 我正在使用python 3.4

Answer 1

我认为这可以帮助您：

from tkinter import *
gui=Tk()
def label():
    global l1,l2,l3,l4
    l1 = Label(gui,text='hi')
    l1.place(x=10,y=10)
    l2 = Label(gui,text='hi2')
    l2.place(x=30,y=10)
    l3 = Label(gui,text='hi3')
    l3.place(x=50,y=10)
    l4 = Label(gui,text='hi4')
    l4.place(x=70,y=10)
def remove_label():
    l1.place_forget()
    l2.place_forget()
    l3.place_forget()
    l4.place_forget()
    print('All cleared!')
b = Button(gui,text='place label',command=label)
b.place(x=10,y=50)
h = Button(gui,text='remove label',command=remove_label)
h.place(x=10,y=100)
gui.mainloop()