[英]Capitalizing the first letter of each sentence in Python
这是我的代码:
def fix_capitalization(usrStr):
newString = ''
wordList = []
numLetters = 0
for s in usrStr.split('. '):
if s[0].isupper():
s = s.capitalize()
s = s.replace(' i ', " I ")
wordList.append(s)
if s.islower():
s = s.capitalize()
s = s.replace(' i ', " I ")
wordList.append(s)
numLetters += 1
if s[0].islower():
s = s.capitalize()
s = s.replace(' i ', " I ")
wordList.append(s)
numLetters += 1
newString = '. '.join(wordList)
return newString, numLetters
传入的字符串是:
i want some water. he has some. maybe he can give me some. i think I will ask.
请注意,在之前maybe
有4个空格。 我想要的结果是:
I want some water. He has some. Maybe he can give me some. I think I will ask.
但我得到:
I want some water. He has some. maybe he can give me some. I think I will ask.
我知道maybe
因为我分手而没有大写.
在句号之后,该句子有多个空格,但是我不确定如何解决这个问题,或者不确定是否有更好的方法来处理我正在做的事情。 任何帮助将不胜感激。
在for循环中:首先找到非空格字符的索引。 然后将s [0]替换为s [index]。
使用正则表达式子方法的解决方案
def fix_capitalization(mystr):
numLettets = 0
newstr = []
for s in mystr.split('. '):
tmp = re.sub('^(\s*\w+)', lambda x:x.group(1).title(), s)
newstr.append(tmp)
# num of letters
if s.lstrip()[0] != tmp.lstrip()[0]:
numLetters += 1
return '. '.join(newstr).replace(' i ', ' I '), numLetters
fix_capitalization( 'i want some water. he has some. maybe he can give me some. i think I will ask.')
# return ('I want some water. He has some. Maybe he can give me some. I think I will ask.', 4)
简单修复如下原始代码
def fix_capitalization(usrStr):
newString = ''
wordList = []
numLetters = 0
for s in usrStr.split('. '):
# check for leading space
lspace = len(s) - len(s.lstrip())
s = s.lstrip()
if s[0].isupper():
s = s.capitalize()
s = s.replace(' i ', " I ")
wordList.append(' '*lspace + s)
if s.islower():
s = s.capitalize()
s = s.replace(' i ', " I ")
wordList.append(' '*lspace + s)
numLetters += 1
if s[0].islower():
s = s.capitalize()
s = s.replace(' i ', " I ")
wordList.append(' '*lspace + s)
numLetters += 1
newString = '. '.join(wordList)
return newString, numLetters
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