在select语句中带有变量的MySQL Cursor

Question

我在存储过程中有以下代码：

DECLARE done INT DEFAULT FALSE;
declare v_degree int(11);
declare v_start_age smallint(6);
declare v_end_age smallint(6);
declare v_gender varchar(20);
declare v_calctable varchar(200);

SELECT calculationtable into v_calctable FROM wac.degrees where tablename = concat("cdb_" + arg_tablename);

declare cur CURSOR for select degree, start_age, end_age, belt, gender from v_calctable;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;

像这样，我将在“将wac.degrees中的table_table = = concat（“ cdb_” + arg_tablename）;的SELECT Calculationtable到v_calctable中的行中得到语法错误。”

如果我将其放在“声明游标”之后，则不会出现语法错误，但是我需要将结果用于de Cursor select语句。

我该怎么做？

谢谢。

Answer 1

CREATE DEFINER=`root`@`localhost` PROCEDURE `my_procedure`()
BEGIN
DECLARE done INT DEFAULT FALSE;
declare v_degree int(11);
declare v_start_age smallint(6);
declare v_end_age smallint(6);
declare v_gender varchar(20);
declare v_calctable varchar(200);

SELECT calculationtable into v_calctable FROM wac.degrees where tablename = concat("cdb_" + arg_tablename);
begin                                                                   -- write here begin keyword
declare cur CURSOR for select degree, start_age, end_age, belt, gender from v_calctable;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;
end;                                                                    -- end here inner block

END

当您通过另一个begin和end关键字使用inner block时，则没有syntask错误。 但是这个程序给您正确的结果还是不明确