在select語句中帶有變量的MySQL Cursor

Question

我在存儲過程中有以下代碼：

DECLARE done INT DEFAULT FALSE;
declare v_degree int(11);
declare v_start_age smallint(6);
declare v_end_age smallint(6);
declare v_gender varchar(20);
declare v_calctable varchar(200);

SELECT calculationtable into v_calctable FROM wac.degrees where tablename = concat("cdb_" + arg_tablename);

declare cur CURSOR for select degree, start_age, end_age, belt, gender from v_calctable;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;

像這樣，我將在“將wac.degrees中的table_table = = concat（“ cdb_” + arg_tablename）;的SELECT Calculationtable到v_calctable中的行中得到語法錯誤。”

如果我將其放在“聲明游標”之后，則不會出現語法錯誤，但是我需要將結果用於de Cursor select語句。

我該怎么做？

謝謝。

Answer 1

CREATE DEFINER=`root`@`localhost` PROCEDURE `my_procedure`()
BEGIN
DECLARE done INT DEFAULT FALSE;
declare v_degree int(11);
declare v_start_age smallint(6);
declare v_end_age smallint(6);
declare v_gender varchar(20);
declare v_calctable varchar(200);

SELECT calculationtable into v_calctable FROM wac.degrees where tablename = concat("cdb_" + arg_tablename);
begin                                                                   -- write here begin keyword
declare cur CURSOR for select degree, start_age, end_age, belt, gender from v_calctable;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;
end;                                                                    -- end here inner block

END

當您通過另一個begin和end關鍵字使用inner block時，則沒有syntask錯誤。 但是這個程序給您正確的結果還是不明確