如何在此代码中仅使用正确的关键字打印链接？

Question

到目前为止，这就是我所拥有的，现在我只需要输出仅是带有“ lion-double-ring”的链接，因为现在idle打印整个信息页面。 这应该循环直到找到链接并使用给定的关键字打印链接。 也许正则表达式是去这里的方法？ 链接

from bs4 import BeautifulSoup
import requests

r = requests.get('walmart.com)
soup = BeautifulSoup(r.text, 'html')
links = soup.find_all('loc')
if "lion" and "double" in str(links):
print str(links)
else:
print('nothing')

Answer 1

from bs4 import BeautifulSoup
import requests

r = requests.get('http://shop.exclucitylife.com/sitemap_products_1.xml?from=1331122689&to=8543902145')
soup = BeautifulSoup(r.text, 'lxml')
links = soup.find_all('loc')
for link in links:
    if 'lion-double-ring' in link.text:
        print(link.text)
        break
else:
    print('nothing')