Python-请求模块-接收流更新-对等重置连接

Question

我已经在一个外汇提供商（OANDA）的实践帐户中构建了自己的python（3.2.1版）交易应用程序，但是在使用基于Linux debian的OS接收流价格时遇到了一些问题。

特别是，我遵循了他们的“ Python流传输率”指南，可在这里找到： http : //developer.oanda.com/rest-live/sample-code/ 。

我有一个线程调用函数“ connect_to_stream”，该函数打印出从服务器接收到的所有滴答声：

streaming_thread = threading.Thread(target=streaming.connect_to_stream, args=[])
streaming_thread.start()

stream.connect_to_stream函数的定义如下：

def connect_to_stream():  

   [..]#provider-related info are passed here

    try:
        s = requests.Session()
        url = "https://" + domain + "/v1/prices"
        headers = {'Authorization' : 'Bearer ' + access_token,
                   'Connection' : 'keep-alive'
                  }
        params = {'instruments' : instruments, 'accountId' : account_id}
        req = requests.Request('GET', url, headers = headers, params = params)
        pre = req.prepare()
        resp = s.send(pre, stream = True, verify = False)
        return resp
    except Exception as e:
        s.close()
        print ("Caught exception when connecting to stream\n%s" % str(e))

    if response.status_code != 200:
            print (response.text)
            return
    for line in response.iter_lines(1):
        if line:
            try:
                msg = json.loads(line)
                print(msg)
            except Exception as e:
                print ("Caught exception when connecting to stream\n%s" % str(e))
                return

msg变量包含为流式传输收到的滴答声。

问题是，我平均会收到三个小时的滴答声，然后断开连接，脚本会挂起而没有收到任何滴答声，或者抛出异常，原因是“对等连接重置”。

您能否对我在这里出什么问题分享任何想法？ 它与请求库（可能是iter_lines）有关吗？

除非引发键盘异常，否则我希望无限期收到报价。

谢谢

Answer 1

对于我来说，服务关闭关闭超过3小时的连接似乎并不奇怪。

确保从幽灵客户端释放服务器套接字对他们而言可能是安全的。

因此，您可能应该在断开连接时重新连接。

try:
    s = requests.Session()
    url = "https://" + domain + "/v1/prices"
    headers = {'Authorization' : 'Bearer ' + access_token,
               'Connection' : 'keep-alive'
              }
    params = {'instruments' : instruments, 'accountId' : account_id}
    req = requests.Request('GET', url, headers = headers, params = params)
    pre = req.prepare()
    resp = s.send(pre, stream = True, verify = False)
    return resp
except SocketError as e:
    if e.errno == errno.ECONNRESET:
        pass # connection has been reset, reconnect.
except Exception as e:
    pass # other exceptions but you'll probably need to reconnect too.