[英]Python: Propagate an exception through a Try/Except Block with multiple Excepts
有没有办法将try / except块中的异常从一个传播到另一个除外?
我想捕获一个特定的错误,然后进行一般的错误处理。
“raise”允许异常“冒泡”到外部try / except,但不在try / except块内引发错误。
理想情况应该是这样的:
import logging
def getList():
try:
newList = ["just", "some", "place", "holders"]
# Maybe from something like: newList = untrustedGetList()
# Faulty List now throws IndexError
someitem = newList[100]
return newList
except IndexError:
# For debugging purposes the content of newList should get logged.
logging.error("IndexError occured with newList containing: \n%s", str(newList))
except:
# General errors should be handled and include the IndexError as well!
logging.error("A general error occured, substituting newList with backup")
newList = ["We", "can", "work", "with", "this", "backup"]
return newList
我遇到的问题是当IndexError被第一个捕获时除外,我的常规错误处理在第二个除了块之外没有应用。
我现在唯一的解决方法是在第一个块中包含一般错误处理代码。 即使我将它包装在它自己的功能块中,它仍然看起来不那么优雅......
您有两种选择:
不要使用专用的except ..
块来捕获IndexError
。 您始终可以通过捕获BaseException
并将异常分配给名称(此处为e
)来手动测试常规块中的异常类型:
try: # ... except BaseException as e: if isinstance(e, IndexError): logging.error("IndexError occured with newList containing: \\n%s", str(newList)) logging.error("A general error occured, substituting newList with backup") newList = ["We", "can", "work", "with", "this", "backup"] return newList
使用嵌套的try..except
语句并重新引发:
try: try: # ... except IndexError: logging.error("IndexError occured with newList containing: \\n%s", str(newList)) raise except: logging.error("A general error occured, substituting newList with backup") newList = ["We", "can", "work", "with", "this", "backup"] return newList
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