[英]Distance between two points using the distance formula
所以我需要计算当前点和参数中指定的另一个点之间的距离并返回计算出的距离
我的打印语句需要看起来像这样:
> print p1.distance(p2)
5.0
我当前的代码:
import math
class Geometry (object):
next_id = 0
def __init__(self):
self.id = Geometry.next_id
Geometry.next_id += 1
geo1 = Geometry()
print geo1.id
geo2 = Geometry()
print geo2.id
class Point(Geometry):
next_id = 0
def __init__(self,x,y,):
self.x = x
self.y = y
self.id = Point.next_id
Point.next_id += 1
def __str__(self):
return "(%0.2f, %0.2f)" % (self.x, self.y)
def identify():
if(p0.id == p1.id):
print "True"
else:
print "False"
def equality():
if (self.x == self.y):
print "True"
else:
print "False"
def distance(p0, p1):
p1 = pts1
pts1 = [(7.35,8.20)]
p0 = pts0
pts0 = [(5,5)]
dist = math.sqrt((p0[0] - p1[0])**2 + (p0[1] - p1[1])**2)
return dist
p0 = Point(5,5)
print p0.id
p1 = Point(7.35,8.20)
print p1.id
print p1
print p0 == p1
print p0.id == p1.id
我不确定如何在Point类中分离x和y值,以用于方程式。
def distance(self, other):
return math.sqrt((self.x - other.x)**2 + (self.y - other.y)**2)
您从未为some_point[index]
定义行为,所以它失败了。 以保存变量的方式访问变量。
您应该使用p0.x
, p0.y
, p1.x
, p1.y
。 但是您不应该覆盖参数变量。
def distance(p0, p1):
dist = math.sqrt((p0.x - p1.x)**2 + (p0.y - p1.y)**2)
return dist
你distance
的方法应该对自己点上运行( self
,因为你在做__str__
),另一点(还不如叫它p
,或可能像other
)。
def distance(self, other):
dist = math.sqrt((other.x - self.x) ** 2 + (other.y - self.y) ** 2)
return dist
使用示例:
p0 = Point(2, 4)
p1 = Point(6, 1)
print(str(p0.distance(p1)))
# 5.0
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.