C#：如何修剪 json 字符串并将值放入正确的类中

Question

我有一个 JSON 字符串，我想将其剪切并将值放入正确的类中。 我如何在 C# 中做到这一点？

{
     \"First\":{\"FirstBool\":1, \"aString\":\"hello\"},
     \"Second\":{\"AnotherBool\":0,\"aString\":\"Hi again\"},
     \"Third\":{\"ThirdBool\":0,\"aString\":\"Hi for the 3rd time\", \"AdditionalString\":\"ADDITIONAL STRING\"}
}

这就是我设置类以获取 JSON 值的方式。

public class First{

public static bool FirstBool {get; set;}
public static string aString {get; set;}

}

public class Second{

public static bool AnotherBool {get; set;}
public static string aString {get; set;}

}

public class Third{

public static bool ThirdBool {get; set;}
public static string aString {get; set;}
public static string AdditionalString {get; set;}

}

Answer 1

首先你的班级看起来像

public class First {
    public int FirstBool { get; set; }
    public string aString { get; set; } 
}

public class Second {
    public int AnotherBool { get; set; }
    public string aString { get; set; } 
}

public class Third {
    public int ThirdBool { get; set; }
    public string aString { get; set; }
    public string AdditionalString { get; set; } 
}

public class Result {
    public First First { get; set; }
    public Second Second { get; set; }
    public Third Third { get; set; } 
}

然后你可以使用 JavaScriptSerializer 反序列化你的 json

JavaScriptSerializer json_serializer = new JavaScriptSerializer();
Result objResult =  (Result)json_serializer.DeserializeObject("<your JSON>");

Answer 2

你的 JSON 字符串First无效，它就像"aString":"hello""应该是"aString":"hello"所以我希望并假设它是一个错字

您可以安装Newtonsoft JSON然后创建类

public class First
{
    [JsonProperty("FirstBool")]
    public int FirstBool { get; set; }

    [JsonProperty("aString")]
    public string aString { get; set; }
}

public class Second
{
    [JsonProperty("AnotherBool")]
    public int AnotherBool { get; set; }

    [JsonProperty("aString")]
    public string aString { get; set; }
}

public class Third
{
    [JsonProperty("ThirdBool")]
    public int ThirdBool { get; set; }

    [JsonProperty("aString")]
    public string aString { get; set; }

    [JsonProperty("AdditionalString")]
    public string AdditionalString { get; set; }
}

public class ClsResult
{
    [JsonProperty("First")]
    public First First { get; set; }

    [JsonProperty("Second")]
    public Second Second { get; set; }

    [JsonProperty("Third")]
    public Third Third { get; set; }
}

并像这样反序列化它

string jsonstr = File.ReadAllText(YourJSONFile);
var ser = JsonConvert.DeserializeObject<ClsResult>(jsonstr);

Answer 3

如果您使用的是 Visual Studio，您可以使用 Edit-> Paste Special -> Paste JSON as classes 找出任何 json 所需的类结构。

创建一个可以反序列化以满足您的要求的根类。

public class Rootobject
{
    public First First { get; set; }
    public Second Second { get; set; }
    public Third Third { get; set; }
}

public class First
{
    public int FirstBool { get; set; }
    public string aString { get; set; }
}

public class Second
{
    public int AnotherBool { get; set; }
    public string aString { get; set; }
}

public class Third
{
    public int ThirdBool { get; set; }
    public string aString { get; set; }
    public string AdditionalString { get; set; }
}