在C ++中，无休止的while循环将在输入字符串==否时结束？

Question

我正在尝试编写一个将两个输入整数相加的代码，并且只要用户希望这样做就一直加一个整数，如果用户要退出，则只需写“ no”。 但是，这不起作用。 当您写“ no”时，它会变得疯狂并增加和减少看似随机的数字。 我的主要功能只是运行inputIntegersUsingLoopAndPrintSum()

void inputIntegersUsingLoopAndPrintSum() {
    int input;
    string answer;

    int sum = inputIntegersAndPrintSum();

    cout << "do you wish to continue? if you don't; write no\n";
    getline(cin, answer); //If you wish to continue
    while (answer != "no") {
        input = inputInteger();
        sum = sum + input;
        cout << "new sum is: " << sum << "\n";
        cout << "do you wish to continue? if you don't; write no\n";
        getline(cin, answer);   
    }


    int inputInteger() {
       int tall;
       cout << "Skriv inn et tall: "; 
       cin >> tall;
       return tall;

       int inputIntegersAndPrintSum() {
           int input1, input2, sum;
           input1 = inputInteger(); //bruker den som returnere en verdi
           input2 = inputInteger();

           sum = input1 + input2;
           cout << "Summen av tallene: " << sum << "\n";
           return sum;
       }

Answer 1

我认为您想得太过分了...请查看此简短程序。

#include <iostream>

int main() {
    char choice = ' ';
    unsigned value = 0;
    unsigned temp = 0;
    std::cout << "Enter a value to be added to." << std::endl;
    std::cin >> value;

    do {
        std::cout << "Enter another value." << std::endl;
        std::cin >> temp;

        value += temp;

        std::cout << value << std::endl;

        std::cout << "Would you like to continue (Y/N)?" << std::endl;
        std::cin >> choice;

    } while ( choice == 'Y' || choice == 'y' );

    return 0;
}