在C ++中，無休止的while循環將在輸入字符串==否時結束？

Question

我正在嘗試編寫一個將兩個輸入整數相加的代碼，並且只要用戶希望這樣做就一直加一個整數，如果用戶要退出，則只需寫“ no”。 但是，這不起作用。 當您寫“ no”時，它會變得瘋狂並增加和減少看似隨機的數字。 我的主要功能只是運行inputIntegersUsingLoopAndPrintSum()

void inputIntegersUsingLoopAndPrintSum() {
    int input;
    string answer;

    int sum = inputIntegersAndPrintSum();

    cout << "do you wish to continue? if you don't; write no\n";
    getline(cin, answer); //If you wish to continue
    while (answer != "no") {
        input = inputInteger();
        sum = sum + input;
        cout << "new sum is: " << sum << "\n";
        cout << "do you wish to continue? if you don't; write no\n";
        getline(cin, answer);   
    }


    int inputInteger() {
       int tall;
       cout << "Skriv inn et tall: "; 
       cin >> tall;
       return tall;

       int inputIntegersAndPrintSum() {
           int input1, input2, sum;
           input1 = inputInteger(); //bruker den som returnere en verdi
           input2 = inputInteger();

           sum = input1 + input2;
           cout << "Summen av tallene: " << sum << "\n";
           return sum;
       }

Answer 1

我認為您想得太過分了...請查看此簡短程序。

#include <iostream>

int main() {
    char choice = ' ';
    unsigned value = 0;
    unsigned temp = 0;
    std::cout << "Enter a value to be added to." << std::endl;
    std::cin >> value;

    do {
        std::cout << "Enter another value." << std::endl;
        std::cin >> temp;

        value += temp;

        std::cout << value << std::endl;

        std::cout << "Would you like to continue (Y/N)?" << std::endl;
        std::cin >> choice;

    } while ( choice == 'Y' || choice == 'y' );

    return 0;
}