如何在python 3.4+中解码JavaScript响应？

Question

我从一个网站得到了这个回应。 我真的不知道如何解码它并获取我想要的信息。

这是JavaScript响应：

{header:{code:0,message:{title:"",detail:""}},body:{parameters:{},dataStores:{"kccjStore":{pageSize:100,pageNumber:1,recordCount:3,name:"kccjStore",rowSetName:"pojo_com.neusoft.education.sysu.xscj.xscjcx.model.KccjModel",order:"kclb asc",metaData:{"jxbmc":{dataType:12},"njzypm":{dataType:12},"xh":{dataType:12},"jxbh":{dataType:12},"sftg":{dataType:12},"zzcj":{dataType:12},"cjzt":{dataType:12},"bzw":{dataType:12},"class":{dataType:12},"xs":{dataType:12},"xq":{dataType:12},"jsxm":{dataType:12},"xnd":{dataType:12},"resource_id":{dataType:12},"jxbpm":{dataType:12},"jd":{dataType:12},"kch":{dataType:12},"kcywmc":{dataType:12},"kcmc":{dataType:12},"khfs":{dataType:12},"cjlcId":{dataType:12},"xf":{dataType:12},"kclb":{dataType:12},"zpcj":{dataType:12}},rowSet:{primary:[{"jxbpm":"79\/93","bzw":"00","cjzt":"2","cjlcId":"11895237815","kcywmc":"Mobile Information Engineering Training:Intermediate ","jxbh":"46000092161002","zpcj":"90","resource_id":"11895237815","xnd":"2016-2017","xq":"1","kch":"46000092","kcmc":"移动信息工程实训（中级）","kclb":"11","xf":"3.0","xs":"72.0","zzcj":"90","jd":"4.0","sftg":"1","xh":"14353379","njzypm":"304\/403","class":"class com.neusoft.education.sysu.xscj.xscjcx.model.KccjModel"},{"jxbpm":"74\/128","bzw":"00","cjzt":"2","cjlcId":"12825792491","kcywmc":"Database Systems Lab","jxbh":"46000085161003","jsxm":"桑应朋","khfs":"03","zpcj":"94","resource_id":"12825792491","xnd":"2016-2017","xq":"1","kch":"46000085","kcmc":"数据库系统实验","kclb":"21","xf":"1.0","xs":"36.0","zzcj":"94","jd":"4.4","sftg":"1","xh":"14353379","njzypm":"157\/403","class":"class com.neusoft.education.sysu.xscj.xscjcx.model.KccjModel"},{"jxbpm":"20\/167","bzw":"00","cjzt":"2","cjlcId":"12825622928","kcywmc":"Database Systems","jxbh":"46000084161001","jsxm":"桑应朋","khfs":"01","zpcj":"87","resource_id":"12825622928","xnd":"2016-2017","xq":"1","kch":"46000084","kcmc":"数据库系统","kclb":"21","xf":"2.0","xs":"36.0","zzcj":"87","jd":"3.7","sftg":"1","xh":"14353379","njzypm":"34\/403","class":"class com.neusoft.education.sysu.xscj.xscjcx.model.KccjModel"}]}}}}}

我正在使用Python 3.4。 下面是我的代码

html_doc = opener.open('http://wjw.sysu.edu.cn/api/score?year=2016-2017&term=1&pylb=01').read().decode('utf-8')

提前致谢！

——————————————————

我之前错误地认为它是JSON文件，并提出了一个错误的问题。 对此我感到抱歉。 但是，谢谢您对我的帮助！ 希望你们中的一些人可以对我的新问题有所帮助！

Answer 1

您的输入有两个问题：

1. 输入上的花括号不平衡。 您缺少左括号， { 。
2. JSON要求所有键都用双引号引起来。 您的输入使用不同的语法，该语法是有效的Javascript，但不是有效的JSON。 您可以分析这样的对象到Python字典，如果你真的要使用第三方的包，如demjson 。

>>> import demjson
>>> parsed = demjson.decode('{header:{code:0,message:{title:"",detail:""}}}')
>>> parsed
{u'header': {u'message': {u'detail': '', u'title': ''}, u'code': 0}}

话虽如此，您使用json.loads本能通常是正确的。 如果您对输入有任何控制（例如，如果可以重写的API或脚本的输出）， 则应重写它以输出严格的JSON ，从而使其可被json.loads解析。

Answer 2

看起来您的数据严格来说不是JSON，因为某些键不是字符串。

另外，似乎缺少匹配的花括号-应该添加为第一个字符，

{header:{code:0,message:{title:"",detail:""}},body:{parameters:{},dataStores:{"kccjStore":{pageSize:100,pageNumber:1,recordCount:3,name:"kccjStore",rowSetName:"pojo_com.neusoft.education.sysu.xscj.xscjcx.model.KccjModel",order:"kclb asc",metaData:{"jxbmc":{dataType:12},"njzypm":{dataType:12},"xh":{dataType:12},"jxbh":{dataType:12},"sftg":{dataType:12},"zzcj":{dataType:12},"cjzt":{dataType:12},"bzw":{dataType:12},"class":{dataType:12},"xs":{dataType:12},"xq":{dataType:12},"jsxm":{dataType:12},"xnd":{dataType:12},"resource_id":{dataType:12},"jxbpm":{dataType:12},"jd":{dataType:12},"kch":{dataType:12},"kcywmc":{dataType:12},"kcmc":{dataType:12},"khfs":{dataType:12},"cjlcId":{dataType:12},"xf":{dataType:12},"kclb":{dataType:12},"zpcj":{dataType:12}},rowSet:{primary:[{"jxbpm":"79\/93","bzw":"00","cjzt":"2","cjlcId":"11895237815","kcywmc":"Mobile Information Engineering Training:Intermediate ","jxbh":"46000092161002","zpcj":"90","resource_id":"11895237815","xnd":"2016-2017","xq":"1","kch":"46000092","kcmc":"移动信息工程实训（中级）","kclb":"11","xf":"3.0","xs":"72.0","zzcj":"90","jd":"4.0","sftg":"1","xh":"14353379","njzypm":"304\/403","class":"class com.neusoft.education.sysu.xscj.xscjcx.model.KccjModel"},{"jxbpm":"74\/128","bzw":"00","cjzt":"2","cjlcId":"12825792491","kcywmc":"Database Systems Lab","jxbh":"46000085161003","jsxm":"桑应朋","khfs":"03","zpcj":"94","resource_id":"12825792491","xnd":"2016-2017","xq":"1","kch":"46000085","kcmc":"数据库系统实验","kclb":"21","xf":"1.0","xs":"36.0","zzcj":"94","jd":"4.4","sftg":"1","xh":"14353379","njzypm":"157\/403","class":"class com.neusoft.education.sysu.xscj.xscjcx.model.KccjModel"},{"jxbpm":"20\/167","bzw":"00","cjzt":"2","cjlcId":"12825622928","kcywmc":"Database Systems","jxbh":"46000084161001","jsxm":"桑应朋","khfs":"01","zpcj":"87","resource_id":"12825622928","xnd":"2016-2017","xq":"1","kch":"46000084","kcmc":"数据库系统","kclb":"21","xf":"2.0","xs":"36.0","zzcj":"87","jd":"3.7","sftg":"1","xh":"14353379","njzypm":"34\/403","class":"class com.neusoft.education.sysu.xscj.xscjcx.model.KccjModel"}]}}}}}

这是w3schools的JSON参考的链接。

这是JSON格式化程序/验证器。

Answer 3

如果您不想使用第三方库，则可以使用正则表达式自己清理数据（例如，在其余属性中添加双引号）：

import re
import json

text = # the input string

p = re.compile(r'({|,)([^{}:"]+):')
text = p.sub(r'\1"\2":', '{' + text)
obj = json.loads(text)

Answer 4

看来您忘记了第一个大括号。 以下代码可以帮助您将数据解析为json：

s = <YOUR DATA>
import json
import re

def repl(m):
    return '"%s":'%m.group(1)

s = re.sub(r'(\w+):', repl, s)
o = json.loads(s)
print o