创建具有多个元素的python列表并写入.csv

Question

我有这个小的代码，每次迭代都会生成一个元素。 还存在用于每个元件产生一个标签。

count = 0
while (count<10):
    random.seed()
    tau = int(math.ceil(np.random.uniform(lorange, hirange)))
    count = count+1
    print('For', count,'th iter tau is', tau)

    X = [amplitude * np.exp(-t / tau)]
    print('And X is', X)

这给了我-

For 1 th iter tau is 253
 And X is [-8.3319888120435905]
For 2 th iter tau is 733
 And X is [-8.5504619226105234]
For 3 th iter tau is 6
 And X is [-1.637157007733484]
For 4 th iter tau is 35
 And X is [-6.5137386619958191]
For 5 th iter tau is 695
 And X is [-8.544086302536952]
For 6 th iter tau is 987
 And X is [-8.5805340921808924]
For 7 th iter tau is 807
 And X is [-8.5611651675760001]
For 8 th iter tau is 820
 And X is [-8.5628471889130697]
For 9 th iter tau is 799
 And X is [-8.5601030426343065]
For 10 th iter tau is 736
 And X is [-8.5509374123154984]

现在，我想获取一个包含所有X值的列表。

我在这里检查了堆栈问题，并做了-

myList = []
myList.append([X for _ in range(no_tau)])
print(myList)

但是，而不是让所有的X元素列表，我收到了多次相同的元素（最后X值）。

[[[-8.5509374123154984], [-8.5509374123154984], [-8.5509374123154984], [-8.5509374123154984], [-8.5509374123154984], [-8.5509374123154984], [-8.5509374123154984], [-8.5509374123154984], [-8.5509374123154984], [-8.5509374123154984]]]

如何获得列表中的所有X元素，而不是多次获得相同的元素？

我也想稍后以.csv格式编写此列表。 任何帮助将不胜感激。 谢谢

Answer 1

X是具有单个元素的列表。 然后，当您这样做时：

myList.append([X for _ in range(no_tau)])

您正在添加具有唯一元素（最后一个） len(range(no_tau))次的列表。

迭代时需要添加它。 像这样：

count = 0
myList = []
while (count<10):
    tau = int(math.ceil(np.random.uniform(lorange, hirange)))
    count = count+1
    X = amplitude * np.exp(-t / tau)
    myList.append(X)

您不需要x是列表，sino un float。 为此，您需要删除[]